As an example on how to compute the s-wave (i.e. angular momentum l=0) scattering length for a given potential we look at the infinitely repulsive spherical
potential well of radius r_0 in 3 dimensions. The radial
Schrödinger equation (l=0) outside of the well is just the same as for a
free particle: :-\frac{\hbar^2}{2m} u''(r)=E u(r), where the hard core potential requires that the
wave function u(r) vanishes at r=r_0, u(r_0)=0. The solution is readily found: :u(r)=A \sin(k r+\delta_s). Here k=\sqrt{2m E}/\hbar and \delta_s=-k \cdot r_0 is the s-wave
phase shift (the phase difference between incoming and outgoing wave), which is fixed by the boundary condition u(r_0)=0; A is an arbitrary normalization constant. One can show that in general \delta_s(k)\approx-k \cdot a_s +O(k^2) for small k (i.e. low energy scattering). The parameter a_s of dimension length is defined as the
scattering length. For our potential we have therefore a=r_0, in other words the scattering length for a
hard sphere is just the radius. (Alternatively one could say that an arbitrary potential with s-wave scattering length a_s has the same low energy scattering properties as a hard sphere of radius a_s.) To relate the scattering length to physical observables that can be measured in a scattering experiment we need to compute the
cross section \sigma. In
scattering theory one writes the asymptotic wavefunction as (we assume there is a finite ranged scatterer at the origin and there is an incoming
plane wave along the z-axis): :\psi(r,\theta)=e^{i k z}+f(\theta) \frac{e^{i k r}}{r} where f is the
scattering amplitude. According to the probability interpretation of quantum mechanics the
differential cross section is given by d\sigma/d\Omega=|f(\theta)|^2 (the probability per unit time to scatter into the direction \mathbf{k}). If we consider only s-wave scattering the differential cross section does not depend on the angle \theta, and the total
scattering cross section is just \sigma=4 \pi |f|^2. The s-wave part of the wavefunction \psi(r,\theta) is projected out by using the standard expansion of a plane wave in terms of spherical waves and
Legendre polynomials P_l(\cos \theta): :e^{i k z}\approx\frac{1}{2 i k r}\sum_{l=0}^{\infty}(2l+1)P_l(\cos \theta)\left[ (-1)^{l+1}e^{-i k r} + e^{i k r}\right] By matching the l=0 component of \psi(r,\theta) to the s-wave solution \psi(r)=A \sin(k r+\delta_s)/r (where we normalize A such that the incoming wave e^{i k z} has a prefactor of unity) one has: :f=\frac{1}{2 i k}(e^{2 i \delta_s}-1)\approx \delta_s/k \approx - a_s This gives: \sigma= \frac{4 \pi}{k^2} \sin^2 \delta_s =4 \pi a_s^2 ==See also==