Standardness of a given probability space \textstyle (\Omega,\mathcal{F},P) is equivalent to a certain property of a measurable map \textstyle f from \textstyle (\Omega,\mathcal{F},P) to a measurable space \textstyle (X,\Sigma). The answer (standard, or not) does not depend on the choice of \textstyle (X,\Sigma) and \textstyle f . This fact is quite useful; one may adapt the choice of \textstyle (X,\Sigma) and \textstyle f to the given \textstyle (\Omega,\mathcal{F},P). No need to examine all cases. It may be convenient to examine a random variable \textstyle f : \Omega \to \mathbb{R}, a random vector \textstyle f : \Omega \to \mathbb{R}^n, a random sequence \textstyle f : \Omega \to \mathbb{R}^\infty, or a sequence of events \textstyle (A_1,A_2,\dots) treated as a sequence of two-valued random variables, \textstyle f : \Omega \to \{0,1\}^\infty. Two conditions will be imposed on \textstyle f (to be
injective, and generating). Below it is assumed that such \textstyle f is given. The question of its existence will be addressed afterwards. The probability space \textstyle (\Omega,\mathcal{F},P) is assumed to be
complete (otherwise it cannot be standard).
A single random variable A measurable function \textstyle f : \Omega \to \mathbb{R} induces a
pushforward measure f_*P, – the probability measure \textstyle \mu on \textstyle \mathbb{R}, defined by : \displaystyle \mu(B) = (f_*P)(B) = P \big( f^{-1}(B) \big) for Borel sets \textstyle B \subset \mathbb{R}. i.e. the
distribution of the random variable f. The image \textstyle f (\Omega) is always a set of full outer measure, : \displaystyle \mu^* \big( f(\Omega) \big) = \inf_{B \supset f(\Omega)}\mu(B) = \inf_{B \supset f(\Omega)}P(f^{-1}(B)) = P(\Omega) = 1, but its
inner measure can differ (see
a perforated interval). In other words, \textstyle f (\Omega) need not be a set of
full measure \textstyle \mu. A measurable function \textstyle f : \Omega \to \mathbb{R} is called
generating if \textstyle \mathcal{F} is the
completion with respect to P of the σ-algebra of inverse images \textstyle f^{-1}(B), where \textstyle B \subset \mathbb{R} runs over all Borel sets.
Caution. The following condition is not sufficient for \textstyle f to be generating: for every \textstyle A \in \mathcal{F} there exists a Borel set \textstyle B \subset \mathbb{R} such that \textstyle P ( A \mathbin{\Delta} f^{-1}(B) ) = 0. (\textstyle \Delta means
symmetric difference).
Theorem. Let a measurable function \textstyle f : \Omega \to \mathbb{R} be injective and generating, then the following two conditions are equivalent: • \mu(\textstyle f (\Omega)) = 1 (i.e. the inner measure has also full measure, and the image \textstyle f (\Omega) is measureable with respect to the completion); • (\Omega,\mathcal{F},P) \, is a standard probability space. See also .
A random vector The same theorem holds for any \mathbb{R}^n \, (in place of \mathbb{R} \,). A measurable function f : \Omega \to \mathbb{R}^n \, may be thought of as a finite sequence of random variables X_1,\dots,X_n : \Omega \to \mathbb{R}, \, and f \, is generating if and only if \mathcal{F} \, is the completion of the σ-algebra generated by X_1,\dots,X_n. \,
A random sequence The theorem still holds for the space \mathbb{R}^\infty \, of infinite sequences. A measurable function f : \Omega \to \mathbb{R}^\infty \, may be thought of as an infinite sequence of random variables X_1,X_2,\dots : \Omega \to \mathbb{R}, \, and f \, is generating if and only if \mathcal{F} \, is the completion of the σ-algebra generated by X_1,X_2,\dots. \,
A sequence of events In particular, if the random variables X_n \, take on only two values 0 and 1, we deal with a measurable function f : \Omega \to \{0,1\}^\infty \, and a sequence of sets A_1,A_2,\ldots \in \mathcal{F}. \, The function f \, is generating if and only if \mathcal{F} \, is the completion of the σ-algebra generated by A_1,A_2,\dots. \, In the pioneering work sequences A_1,A_2,\ldots \, that correspond to injective, generating f \, are called
bases of the probability space (\Omega,\mathcal{F},P) \, (see ). A basis is called complete mod 0, if f(\Omega) \, is of full measure \mu, \, see . In the same section Rokhlin proved that if a probability space is complete mod 0 with respect to some basis, then it is complete mod 0 with respect to every other basis, and defines
Lebesgue spaces by this completeness property. See also and .
Additional remarks The four cases treated above are mutually equivalent, and can be united, since the measurable spaces \mathbb{R}, \, \mathbb{R}^n, \, \mathbb{R}^\infty \, and \{0,1\}^\infty \, are mutually isomorphic; they all are
standard measurable spaces (in other words, standard Borel spaces). Existence of an injective measurable function from \textstyle (\Omega,\mathcal{F},P) to a standard measurable space \textstyle (X,\Sigma) does not depend on the choice of \textstyle (X,\Sigma). Taking \textstyle (X,\Sigma) = \{0,1\}^\infty we get the property well known as being
countably separated (but called
separable in ). Existence of a generating measurable function from \textstyle (\Omega,\mathcal{F},P) to a standard measurable space \textstyle (X,\Sigma) also does not depend on the choice of \textstyle (X,\Sigma). Taking \textstyle (X,\Sigma) = \{0,1\}^\infty we get the property well known as being
countably generated (mod 0), see . Every injective measurable function from a
standard probability space to a
standard measurable space is generating. See , , . This property does not hold for the non-standard probability space dealt with in the subsection "A superfluous measurable set" above.
Caution. The property of being countably generated is invariant under mod 0 isomorphisms, but the property of being countably separated is not. In fact, a standard probability space \textstyle (\Omega,\mathcal{F},P) is countably separated if and only if the
cardinality of \textstyle \Omega does not exceed
continuum (see ). A standard probability space may contain a null set of any cardinality, thus, it need not be countably separated. However, it always contains a countably separated subset of full measure. == Equivalent definitions ==