The centers of the circles of a Steiner chain lie on a
conic section. For example, if the smaller given circle lies within the larger, the centers lie on an
ellipse. This is true for any set of circles that are internally tangent to one given circle and externally tangent to the other; such systems of circles appear in the
Pappus chain, the
problem of Apollonius, and the three-dimensional
Soddy's hexlet. Similarly, if some circles of the Steiner chain are externally tangent to both given circles, their centers must lie on a hyperbola, whereas those that are internally tangent to both lie on a different hyperbola. The circles of the Steiner chain are tangent to two fixed circles, denoted here as
α and
β, where
β is enclosed by
α. Let the radii of these two circles be denoted as
rα and
rβ, respectively, and let their respective centers be the points
A and
B. Let the radius, diameter and center point of the
kth circle of the Steiner chain be denoted as
rk,
dk and
Pk, respectively. All the centers of the circles in the Steiner chain are located on a common
ellipse, for the following reason. The sum of the distances from the center point of the
kth circle of the Steiner chain to the two centers
A and
B of the fixed circles equals a constant : \overline{\mathbf{P}_k\mathbf{A}} + \overline{\mathbf{P}_k \mathbf{B}} = (r_\alpha - r_k) + \left( r_\beta + r_k \right) = r_\alpha + r_\beta Thus, for all the centers of the circles of the Steiner chain, the sum of distances to
A and
B equals the same constant,
rα +
rβ. This defines an ellipse, whose two
foci are the points
A and
B, the centers of the circles,
α and
β, that sandwich the Steiner chain of circles. The sum of distances to the foci equals twice the
semi-major axis a of an ellipse; hence, : 2a = r_\alpha + r_\beta Let
p equal the distance between the foci,
A and
B. Then, the
eccentricity e is defined by 2
ae =
p, or : e = \frac{p}{2a} = \frac{p}{r_{\alpha} + r_{\beta}} From these parameters, the
semi-minor axis b and the
semi-latus rectum L can be determined : b^2 = a^2 \left( 1 - e^2 \right) = a^2 - \frac{p^2}{4} : L = \frac{b^2}{a} = a - \frac{p^2}{4a} Therefore, the ellipse can be described by an equation in terms of its distance
d to one focus : d = \frac{L}{1 - e \cos \theta} where
θ is the angle with the line joining the two foci. ==Conjugate chains==