Isotropic For a linear isotropic material subjected only to compressive (i.e. normal) forces, the deformation of a material in the direction of one axis will produce a deformation of the material along the other axis in three dimensions. Thus it is possible to generalize
Hooke's law (for compressive forces) into three dimensions: :\begin{align} \varepsilon_{xx} &= \frac {1}{E} \left [ \sigma_{xx} - \nu \left ( \sigma_{yy} + \sigma_{zz} \right ) \right ] \\[6px] \varepsilon_{yy} &= \frac {1}{E} \left [ \sigma_{yy} - \nu \left ( \sigma_{zz} + \sigma_{xx} \right ) \right ] \\[6px] \varepsilon_{zz} &= \frac {1}{E} \left [ \sigma_{zz} - \nu \left ( \sigma_{xx} + \sigma_{yy} \right ) \right ] \end{align} where: • , , and are
strain in the direction of , and • , , and are
stress in the direction of , and • is
Young's modulus (the same in all directions for isotropic materials) • is Poisson's ratio (the same in all directions for isotropic materials) these equations can be all synthesized in the following: : \varepsilon_{ii} = \frac {1}{E} \left [ \sigma_{ii}(1+\nu) - \nu \sum_k \sigma_{kk} \right ] In the most general case, also
shear stresses will hold as well as normal stresses, and the full generalization of Hooke's law is given by: : \varepsilon_{ij} = \frac {1}{E} \left [ \sigma_{ij}(1+\nu) - \nu \delta_{ij} \sum_k \sigma_{kk} \right ] where is the
Kronecker delta. The
Einstein notation is usually adopted: : \sigma_{kk} \equiv \sum_l \delta_{kl} \sigma_{kl} to write the equation simply as: : \varepsilon_{ij} = \frac {1}{E} \left [ \sigma_{ij}(1+\nu) - \nu \delta_{ij} \sigma_{kk} \right]
Anisotropic For anisotropic materials, the Poisson ratio depends on the direction of extension and transverse deformation : \begin{align} \nu (\mathbf{n}, \mathbf{m}) &= - E\left(\mathbf n\right) s_{ij \alpha \beta} n_i n_j m_\alpha m_\beta \\[4px] E^{-1} (\mathbf{n}) &= s_{ij\alpha \beta } n_i n_j n_\alpha n_\beta \end{align} Here is Poisson's ratio, is
Young's modulus, is a unit vector directed along the direction of extension, is a unit vector directed perpendicular to the direction of extension. Poisson's ratio has a different number of special directions depending on the type of anisotropy.
Orthotropic Orthotropic materials have three mutually perpendicular planes of symmetry in their material properties. An example is wood, which is most stiff (and strong) along the grain, and less so in the other directions. Then
Hooke's law can be expressed in
matrix form as : \begin{bmatrix} \epsilon_{xx} \\ \epsilon_{yy} \\ \epsilon_{zz} \\ 2\epsilon_{yz} \\ 2\epsilon_{zx} \\ 2\epsilon_{xy} \end{bmatrix} = \begin{bmatrix} \tfrac{1}{E_x} & - \tfrac{\nu_{yx}}{E_y} & - \tfrac{\nu_{zx}}{E_z} & 0 & 0 & 0 \\ -\tfrac{\nu_{xy}}{E_x} & \tfrac{1}{E_y} & - \tfrac{\nu_{zy}}{E_z} & 0 & 0 & 0 \\ -\tfrac{\nu_{xz}}{E_x} & - \tfrac{\nu_{yz}}{E_y} & \tfrac{1}{E_z} & 0 & 0 & 0 \\ 0 & 0 & 0 & \tfrac{1}{G_{yz}} & 0 & 0 \\ 0 & 0 & 0 & 0 & \tfrac{1}{G_{zx}} & 0 \\ 0 & 0 & 0 & 0 & 0 & \tfrac{1}{G_{xy}} \\ \end{bmatrix} \begin{bmatrix} \sigma_{xx} \\ \sigma_{yy} \\ \sigma_{zz} \\ \sigma_{yz} \\ \sigma_{zx} \\ \sigma_{xy} \end{bmatrix} where • is the
Young's modulus along axis • is the
shear modulus in direction on the plane whose normal is in direction • is the Poisson ratio that corresponds to a contraction in direction when an extension is applied in direction . The Poisson ratio of an orthotropic material is different in each direction (, and ). However, the symmetry of the stress and strain tensors implies that not all the six Poisson's ratios in the equation are independent. There are only nine independent material properties: three elastic moduli, three shear moduli, and three Poisson's ratios. The remaining three Poisson's ratios can be obtained from the relations :\frac{\nu_{yx}}{E_y} = \frac{\nu_{xy}}{E_x}\,, \qquad \frac{\nu_{zx}}{E_z} = \frac{\nu_{xz}}{E_x}\,, \qquad \frac{\nu_{yz}}{E_y} = \frac{\nu_{zy}}{E_z} From the above relations we can see that if then . The larger ratio (in this case ) is called the
major Poisson ratio while the smaller one (in this case ) is called the
minor Poisson ratio. We can find similar relations between the other Poisson ratios. \begin{bmatrix} \epsilon_{11} \\ \epsilon_{22} \\ \epsilon_{33} \\ 2\epsilon_{23} \\ 2\epsilon_{31} \\ 2\epsilon_{12} \end{bmatrix} = \begin{bmatrix} \tfrac{1}{E_1} & - \tfrac{\nu_{21}}{E_2} & - \tfrac{\nu_{31}}{E_3} & 0 & 0 & 0 \\ -\tfrac{\nu_{12}}{E_1} & \tfrac{1}{E_2} & - \tfrac{\nu_{32}}{E_3} & 0 & 0 & 0 \\ -\tfrac{\nu_{13}}{E_1} & - \tfrac{\nu_{23}}{E_2} & \tfrac{1}{E_3} & 0 & 0 & 0 \\ 0 & 0 & 0 & \tfrac{1}{G_{23}} & 0 & 0 \\ 0 & 0 & 0 & 0 & \tfrac{1}{G_{13}} & 0 \\ 0 & 0 & 0 & 0 & 0 & \tfrac{1}{G_{12}} \end{bmatrix} \begin{bmatrix} \sigma_{11} \\ \sigma_{22} \\ \sigma_{33} \\ \sigma_{23} \\ \sigma_{31} \\ \sigma_{12} \end{bmatrix} -->
Transversely isotropic Transversely isotropic materials have
a plane of isotropy in which the elastic properties are isotropic. If we assume that this plane of isotropy is the -plane, then Hooke's law takes the form : \begin{bmatrix} \epsilon_{xx} \\ \epsilon_{yy} \\ \epsilon_{zz} \\ 2\epsilon_{yz} \\ 2\epsilon_{zx} \\ 2\epsilon_{xy} \end{bmatrix} = \begin{bmatrix} \tfrac{1}{E_x} & - \tfrac{\nu_{yx}}{E_y} & - \tfrac{\nu_{zx}}{E_z} & 0 & 0 & 0 \\ -\tfrac{\nu_{xy}}{E_x} & \tfrac{1}{E_y} & - \tfrac{\nu_{zy}}{E_z} & 0 & 0 & 0 \\ -\tfrac{\nu_{xz}}{E_x} & - \tfrac{\nu_{yz}}{E_y} & \tfrac{1}{E_z} & 0 & 0 & 0 \\ 0 & 0 & 0 & \tfrac{1}{G_{\rm yz}} & 0 & 0 \\ 0 & 0 & 0 & 0 & \tfrac{1}{G_{\rm zx}} & 0 \\ 0 & 0 & 0 & 0 & 0 & \tfrac{1}{G_{\rm xy}} \\ \end{bmatrix} \begin{bmatrix} \sigma_{xx} \\ \sigma_{yy} \\ \sigma_{zz} \\ \sigma_{yz} \\ \sigma_{zx} \\ \sigma_{xy} \end{bmatrix} where we have used the -plane of isotropy to reduce the number of constants, that is, :E_y = E_z,\qquad \nu_{xy} = \nu_{xz},\qquad \nu_{yx} = \nu_{zx} .. The symmetry of the stress and strain tensors implies that : \frac{\nu_{xy}}{E_x} = \frac{\nu_{yx}}{E_y} ,\qquad \nu_{yz} = \nu_{zy} . This leaves us with six independent constants , , , , , . However, transverse isotropy gives rise to a further constraint between and , which is : G_{yz} = \frac{E_y}{2\left(1+\nu_{yz}\right)} . Therefore, there are five independent elastic material properties, two of which are Poisson's ratios. For the assumed plane of symmetry, the larger of and is the major Poisson ratio. The other major and minor Poisson ratios are equal. == Poisson's ratio values for different materials ==