Since Sylow's theorem ensures the existence of p-subgroups of a finite group, it is worthwhile to study groups of prime power order more closely. Most of the examples use Sylow's theorem to prove that a group of a particular order is not
simple. For groups of small order, the congruence condition of Sylow's theorem is often sufficient to force the existence of a
normal subgroup.
Burnside's pa qb theorem states that if the order of a group is the product of one or two
prime powers, then it is
solvable, hence not not simple (except if it is cyclic of prime order).
Cyclic group orders Some non-prime numbers
n are such that every group of order
n is cyclic. One can show that
n = 15 is such a number using the Sylow theorems: Let
G be a group of order 15 = 3 · 5 and
n3 be the number of Sylow 3-subgroups. Then
n3 \mid 5 and
n3 ≡ 1 (mod 3). The only value satisfying these constraints is 1; therefore, there is only one subgroup of order 3, and it must be
normal (since it has no distinct conjugates). Similarly,
n5 must divide 3, and
n5 must equal 1 (mod 5); thus it must also have a single normal subgroup of order 5. Since 3 and 5 are
coprime, the intersection of these two subgroups is trivial, and so
G must be the
internal direct product of groups of order 3 and 5, that is the
cyclic group of order 15. Thus, there is only one group of order 15 (
up to isomorphism). More generally, one can show with a similar argument that if
n =
pq, where
p and
q are distinct prime numbers such that
p does not divide
q-1, then every group of order
n is cyclic. The condition of
p not dividing
q-1 is necessary: as an example, the
dihedral group Dp, where
p is an odd prime, has order
2p but is not cyclic.
Small groups are not simple A more complicated application is to find the order of the smallest
simple group that is not
cyclic.
Burnside's pa qb theorem rules out every group up to order 30 . If |
G| = 30 and
G were simple, then
n3 > 1 to avoid a normal 3-subgroup, and
n3 must both divide 10 = 2 · 5 and equal 1 (mod 3), hence
n3 = 10. The group then has 10 distinct cyclic subgroups of order 3, each with 2 elements of order 3. This means
G has at least 20 distinct elements of order 3. Similarly,
n5 = 6, since
n5 > 1 must divide 6 = 2 · 3, and
n5 must equal 1 (mod 5). Thus
G also has 24 distinct elements of order 5. But the order of
G is only 30, so a simple group of order 30 cannot exist. Next suppose |
G| = 42 = 2 · 3 · 7 and
G were simple. Here
n7 > 1 must divide 6 = 2 · 3 and
n7 must equal 1 (mod 7), which is impossible. On the other hand, if |
G| = 60 = 22 · 3 · 5, then
n3 = 10 and
n5 = 6 is perfectly possible. In fact, the smallest simple non-cyclic group is
A5, the
alternating group over 5 elements. It has order 60, and has 24
cyclic permutations of order 5, and 20 of order 3. In fact, if |
G| = 60 and
n5 > 1, then G is simple.
Wilson's theorem Part of
Wilson's theorem states that :(p-1)! \equiv -1 \pmod p for every prime
p. One may easily prove this theorem by Sylow's third theorem. Indeed, observe that the number
np of Sylow's
p-subgroups in the symmetric group
Sp is times the number of p-cycles in
Sp, ie. . On the other hand, . Hence, . So, .
Fusion results Frattini's argument shows that a Sylow subgroup of a normal subgroup provides a factorization of a finite group. A slight generalization known as '''Burnside's fusion theorem'
states that if G
is a finite group with Sylow p
-subgroup P
and two subsets A
and B
normalized by P
, then A
and B
are G
-conjugate if and only if they are NG
(P'')-conjugate. The proof is a simple application of Sylow's theorem: If
B=
Ag, then the normalizer of
B contains not only
P but also
Pg (since
Pg is contained in the normalizer of
Ag). By Sylow's theorem
P and
Pg are conjugate not only in
G, but in the normalizer of
B. Hence
gh−1 normalizes
P for some
h that normalizes
B, and then
Agh−1 =
Bh−1 =
B, so that
A and
B are
NG(
P)-conjugate. Burnside's fusion theorem can be used to give a more powerful factorization called a
semidirect product: if
G is a finite group whose Sylow
p-subgroup
P is contained in the center of its normalizer, then
G has a normal subgroup
K of order coprime to
P,
G =
PK and
P∩
K = {1}, that is,
G is
p-nilpotent. Less trivial applications of the Sylow theorems include the
focal subgroup theorem, which studies the control a Sylow
p-subgroup of the
derived subgroup has on the structure of the entire group. This control is exploited at several stages of the
classification of finite simple groups, and for instance defines the case divisions used in the
Alperin–Brauer–Gorenstein theorem classifying finite
simple groups whose Sylow 2-subgroup is a
quasi-dihedral group. These rely on
J. L. Alperin's strengthening of the conjugacy portion of Sylow's theorem to control what sorts of elements are used in the conjugation. ==Proof of the Sylow theorems==