If
i j ≡ 1 (mod
si). Therefore, every two numbers in Sylvester's sequence are
relatively prime. The sequence can be used to prove that there are infinitely many
prime numbers, as any prime can divide at most one number in the sequence. More strongly, no prime factor of a number in the sequence can be
congruent to 5 modulo 6, and the sequence can be used to prove that there are infinitely many primes congruent to 7 modulo 12. No term can be a
perfect power. Much remains unknown about the factorization of the numbers in Sylvester's sequence. For instance, it is not known if all numbers in the sequence are
squarefree, although all the known terms are. As describes, it is easy to determine which Sylvester number (if any) a given prime
p divides: simply compute the recurrence defining the numbers modulo
p until finding either a number that is congruent to zero (mod
p) or finding a repeated modulus. Using this technique he found that 1166 out of the first three million primes are
divisors of Sylvester numbers, and that none of these primes has a square that divides a Sylvester number. The set of primes that can occur as factors of Sylvester numbers is of density zero in the set of all primes: indeed, the number of such primes less than
x is O(\pi(x) / \log\log\log x). The following table shows known factorizations of these numbers (except
s0 ...
s3, which are all prime): As is customary, P
n and C
n denote prime numbers and unfactored
composite numbers
n digits long. == Applications ==