The
radio horizon is the
locus of points at which direct rays from an
antenna are tangential to the surface of the Earth. If the Earth were a perfect sphere without an atmosphere, the
radio horizon would be a circle. The radio horizon of the transmitting and receiving antennas can be added together to increase the effective communication range.
Radio wave propagation is affected by atmospheric conditions,
ionospheric absorption, and the presence of obstructions, for example mountains or trees. Simple formulas that include the effect of the atmosphere give the range as: :\mathrm{horizon}_\mathrm{mi} \approx 1.23 \cdot \sqrt{\mathrm{height}_\mathrm{feet}} :\mathrm{horizon}_\mathrm{km} \approx 3.57 \cdot \sqrt{\mathrm{height}_\mathrm{metres}} The simple formulas give a best-case approximation of the maximum propagation distance, but are not sufficient to estimate the quality of service at any location.
Earth bulge In
telecommunications,
Earth bulge refers to the effect of
earth's curvature on radio propagation. It is a consequence of a circular segment of earth profile that blocks off long-distance communications. Since the vacuum line of sight passes at varying heights over the Earth, the propagating radio wave encounters slightly different propagation conditions over the path.
Vacuum distance to horizon Assuming a perfect sphere with no terrain irregularity, the distance to the horizon from a high altitude
transmitter (i.e., line of sight) can readily be calculated. Let
R be the radius of the Earth and
h be the altitude of a telecommunication station. The line of sight distance
d of this station is given by the
Pythagorean theorem; : d^2=(R+h)^{2}-R^2= 2\cdot R \cdot h +h^2 The altitude of the station
h is much smaller than the radius of the Earth
R. Therefore, h^2 can be neglected compared with 2\cdot R \cdot h. Thus: : d \approx \sqrt{ 2\cdot R \cdot h} If the height
h is given in metres, and distance
d in kilometres, : d \approx 3.57 \cdot \sqrt{h} If the height
h is given in feet, and the distance
d in statute miles, : d \approx 1.23 \cdot \sqrt{h} In the case, when there are two stations involve, e.g. a transmit station on ground with a station height
h and a receive station in the air with a station height
H, the line of sight distance can be calculated as follows: d \thickapprox \sqrt{2 R} \, \left( \sqrt{h} + \sqrt{H}\right)
Atmospheric refraction The usual effect of the declining pressure of the atmosphere with height (
vertical pressure variation) is to bend (
refract) radio waves down towards the surface of the Earth. This results in an
effective Earth radius, increased by a factor around . This
k-factor can change from its average value depending on weather.
Refracted distance to horizon The previous vacuum distance analysis does not consider the effect of atmosphere on the propagation path of RF signals. In fact, RF signals do not propagate in straight lines: Because of the refractive effects of atmospheric layers, the propagation paths are somewhat curved. Thus, the maximum service range of the station is not equal to the line of sight vacuum distance. Usually, a factor
k is used in the equation above, modified to be : d \approx \sqrt{2 \cdot k \cdot R \cdot h}
k > 1 means geometrically reduced bulge and a longer service range. On the other hand,
k d \approx 4.12 \cdot \sqrt{h} for
h in metres and
d in kilometres; or : d \approx 1.41 \cdot\sqrt{h} for
h in feet and
d in miles. But in stormy weather,
k may decrease to cause
fading in transmission. (In extreme cases
k can be less than 1.) That is equivalent to a hypothetical decrease in Earth radius and an increase of Earth bulge. For example, in normal weather conditions, the service range of a station at an altitude of 1500 m with respect to receivers at sea level can be found as, : d \approx 4.12 \cdot \sqrt{1500} = 160 \mbox { km.} == See also ==