The significance of this construction begins with the following result, which belongs to the subject of
cohomology of
fiber bundles. (We have stated the result in terms of \Z_2
coefficients to avoid complications arising from
orientability; see also Orientation of a vector bundle#Thom space.) Let p: E\to B be a real vector bundle of rank
n. Then there is an isomorphism called a
Thom isomorphism :\Phi : H^k(B; \Z_2) \to \widetilde{H}^{k+n}(T(E); \Z_2), for all
k greater than or equal to 0, where the
right hand side is
reduced cohomology. This theorem was formulated and proved by
René Thom in his famous 1952 thesis. We can interpret the theorem as a global generalization of the suspension isomorphism on local trivializations, because the Thom space of a trivial bundle on
B of rank
k is isomorphic to the
kth suspension of B_+,
B with a disjoint point added (cf. #Construction of the Thom space.) This can be more easily seen in the formulation of the theorem that does not make reference to Thom space: {{math_theorem|name=Thom isomorphism| Let \Lambda be a ring and p: E\to B be an
oriented real vector bundle of rank
n. Then there exists a class :u \in H^n(E, E \setminus B; \Lambda), where
B is embedded into
E as a zero section, such that for any fiber
F the restriction of
u :u|_{(F, F \setminus 0)} \in H^n(F, F \setminus 0; \Lambda) is the class induced by the orientation of
F. Moreover, :\begin{cases} H^k(E; \Lambda) \to H^{k+n}(E, E \setminus B; \Lambda) \\ x \longmapsto x \smile u \end{cases} is an isomorphism. }} In concise terms, the last part of the theorem says that
u freely generates H^*(E, E \setminus B; \Lambda) as a right H^*(E; \Lambda)-module. The class
u is usually called the
Thom class of
E. Since the pullback p^*: H^*(B; \Lambda) \to H^*(E; \Lambda) is a
ring isomorphism, \Phi is given by the equation: :\Phi(b) = p^*(b) \smile u. In particular, the Thom isomorphism sends the
identity element of H^*(B) to
u. Note: for this formula to make sense,
u is treated as an element of (we drop the ring \Lambda) :\tilde{H}^n(T(E)) = H^n(\operatorname{Sph}(E), B) \simeq H^n(E, E \setminus B).H^k(D(E),\operatorname{Sph}(E);\Z_2)\cong \tilde H^k(T(E);\Z_2), where D(E) is the associated disk bundle, so we have a cup product :H^i(D(E);\Z_2)\otimes H^k(D(E),\operatorname{Sph}(E);\Z_2)\to H^{i+k}(D(E),\operatorname{Sph}(E);\Z_2)\cong \tilde H^k(T(E);\Z_2).--> The standard reference for the Thom isomorphism is the book by Bott and Tu. ==Significance of Thom's work==