A tournament in which ((a \rightarrow b) and (b \rightarrow c)) \Rightarrow (a \rightarrow c) is called
transitive. In other words, in a transitive tournament, the vertices may be (strictly)
totally ordered by the edge relation, and the edge relation is the same as
reachability.
Equivalent conditions The following statements are equivalent for a tournament T on n vertices: • T is transitive. • T is a strict total ordering. • T is
acyclic. • T does not contain a cycle of length 3. • The score sequence (set of outdegrees) of T is \{0,1,2,\ldots,n-1\}. • T has exactly one Hamiltonian path.
Ramsey theory Transitive tournaments play a role in
Ramsey theory analogous to that of
cliques in undirected graphs. In particular, every tournament on n vertices contains a transitive subtournament on 1+\lfloor\log_2 n\rfloor vertices. The proof is simple: choose any one vertex v to be part of this subtournament, and form the rest of the subtournament recursively on either the set of incoming neighbors of v or the set of outgoing neighbors of v, whichever is larger. For instance, every tournament on seven vertices contains a three-vertex transitive subtournament; the
Paley tournament on seven vertices shows that this is the most that can be guaranteed. However, showed that this bound is not tight for some larger values of n. proved that there are tournaments on n vertices without a transitive subtournament of size 2+2\lfloor\log_2 n\rfloor Their proof uses a
counting argument: the number of ways that a k-element transitive tournament can occur as a subtournament of a larger tournament on n labeled vertices is \binom{n}{k}k!2^{\binom{n}{2}-\binom{k}{2}}, and when k is larger than 2+2\lfloor\log_2 n\rfloor, this number is too small to allow for an occurrence of a transitive tournament within each of the 2^{\binom{n}{2}} different tournaments on the same set of n labeled vertices.
Paradoxical tournaments A player who wins all games would naturally be the tournament's winner. However, as the existence of non-transitive tournaments shows, there may not be such a player. A tournament for which every player loses at least one game is called a 1-paradoxical tournament. More generally, a tournament T=(V,E) is called k-paradoxical if for every k-element subset S of V there is a vertex v_0 in V\setminus S such that v_0 \rightarrow v for all v \in S. By means of the
probabilistic method,
Paul Erdős showed that for any fixed value of k, if |V| \geq k^22^k\ln(2+o(1)), then almost every tournament on V is k-paradoxical. On the other hand, an easy argument shows that any k-paradoxical tournament must have at least 2^{k+1}-1 players, which was improved to (k+2)2^{k-1}-1 by
Esther and
George Szekeres in 1965. There is an explicit construction of k-paradoxical tournaments with k^24^{k-1}(1+o(1)) players by
Graham and Spencer (1971) namely the
Paley tournament.
Condensation The
condensation of any tournament is itself a transitive tournament. Thus, even for tournaments that are not transitive, the strongly connected components of the tournament may be totally ordered. ==Score sequences and score sets==