Notice that C∞(
M,
N) has infinite dimension, whereas J
k(
M,
N) has finite dimension. In fact, J
k(
M,
N) is a real, finite-dimensional manifold. To see this, let denote the space of
polynomials, with real coefficients, in
m variables of order at most
k and with zero as the
constant term. This is a real
vector space with dimension : \dim\left\{\R^k[x_1,\ldots,x_m]\right\} = \sum_{i=1}^k \frac{(m+i-1)!}{(m-1)! \cdot i!} = \left( \frac{(m+k)!}{m!\cdot k!} - 1 \right) . Writing {{nowrap|1=
a = dim{ℝ
k[
x1,...,
xm]}}} then, by the standard theory of vector spaces and so is a real, finite-dimensional manifold. Next, define: :B_{m,n}^k = \bigoplus_{i=1}^n \R^k[x_1,\ldots,x_m], \implies \dim\left\{B_{m,n}^k\right\} = n \dim \left\{ A_m^k \right\} = n \left( \frac{(m+k)!}{m!\cdot k!} - 1 \right) . Using
b to denote the dimension ''B'
k'm
,n'', we see that , and so is a real, finite-dimensional manifold. In fact, if
M and
N have dimension
m and
n respectively then: : \dim\!\left\{J^k(M,N)\right\} = m + n + \dim \!\left\{B_{n,m}^k\right\} = m + n\left( \frac{(m+k)!}{m!\cdot k!}\right). ==Topology==