Various proofs of the theorem have been given by Hilton, Liebman,
Laue, Herring, and a rather extensive treatment by Cerf. The following is after the method of R. F. Strickland-Constable. We begin with the surface energy for a crystal :\Delta G_{i}= \sum_{j}\gamma_j O_j \,\! which is the product of the surface energy per unit area times the area of each face, summed over all faces. This is minimized for a given volume when :\delta \left(\sum_{j}\gamma_j O_j\right)_{V_c} = \sum_{j}\gamma_j \delta (O_j)_{V_c} = 0\,\! Surface free energy, being an
intensive property, does not vary with volume. We then consider a small change in shape for a constant volume. If a crystal were nucleated to a thermodynamically unstable state, then the change it would undergo afterward to approach an equilibrium shape would be under the condition of constant volume. By definition of holding a variable constant, the change must be zero, \delta (V_c)_{V_c} = 0 . Then by expanding V_c in terms of the surface areas O_j and heights h_j of the crystal faces, one obtains :\delta (V_c)_{V_c} =\frac{1}{3} \delta \left(\sum_{j} h_j O_j\right)_{V_c} = 0 , which can be written, by applying the
product rule, as : \sum_{j}h_j \delta (O_j)_{V_c} + \sum_{j}O_j\delta (h_j)_{V_c}= 0 \,\!. The second term must be zero, that is, O_1 \delta (h_1)_{V_c} + O_2 \delta (h_2)_{V_c} + \ldots = 0 This is because, if the volume is to remain constant, the changes in the heights of the various faces must be such that when multiplied by their surface areas the sum is zero. If there were only two surfaces with appreciable area, as in a pancake-like crystal, then O_1/O_2 = -\delta(h_1)_{V_c}/\delta (h_2)_{V_c}. In the pancake instance, O_1 = O_2 on premise. Then by the condition, \delta(h_1)_{V_c} = - \delta(h_2)_{V_c}. This is in agreement with a simple geometric argument considering the pancake to be a cylinder with very small
aspect ratio. The general result is taken here without proof. This result imposes that the remaining sum also equal 0, :\sum_{j}h_j \delta (O_j)_{V_c} = 0 \,\! Again, the surface energy minimization condition is that :\sum_{j}\gamma_j \delta (O_j)_{V_c} = 0\,\! These may be combined, employing a constant of proportionality \lambda for generality, to yield :\sum_{j}(h_i - \lambda \gamma_j) \delta (O_j)_{V_c} = 0\,\! The change in shape \delta (O_j)_{V_c} must be allowed to be arbitrary, which then requires that h_j=\lambda \gamma_j, which then proves the Gibbs-Wulff Theorem. == See also ==