• According to the intermediate-value theorem, every continuous real function f has the intermediate-value property: on every interval (
a,
b), the function f passes through every point between f(a) and f(b). The Conway base-13 function shows that the converse is false: it satisfies the intermediate-value property, but is not continuous. • In fact, the Conway base-13 function satisfies a much stronger intermediate-value property—on every interval (
a,
b), the function f passes through
every real number. As a result, it satisfies a much stronger discontinuity property— it is discontinuous everywhere. • From the above follows even more regarding the discontinuity of the function - its graph is dense in \mathbb{R}^2 • To prove that Conway's base-13 function satisfies this stronger intermediate property, let (
a,
b) be an interval, let
c be a point in that interval, and let
r be any real number. Create a base-13 encoding of
r as follows: starting with the base-10 representation of
r, replace the decimal point with C and indicate the sign of
r by prepending either an A (if
r is positive) or a B (if
r is negative) to the beginning. By definition of Conway's base-13 function, the resulting string \hat{r} has the property that f(\hat{r}) = r. Moreover,
any base-13 string that ends in \hat{r} will have this property. Thus, if we replace the tail end of
c with \hat{r}, the resulting number will have
f(
c) =
r. By introducing this modification sufficiently far along the tridecimal representation of c, you can ensure that the new number c' will still lie in the interval (a, b). This proves that for any number
r, in every interval we can find a point c' such that f(c') = r. • Conway's base-13 function maps
almost all the reals in any interval to 0. ==See also==