The
reaction mechanism begins with an imine condensation of a primary aromatic amine and
formaldehyde Once the imine is produced, it reacts with
phenol in the presence of water to yield an α-aminobenzylphenol. First, the lone-pair on the nitrogen of the imine
deprotonates the phenol, pushing the
bonding
electrons onto the oxygen. The
carbonyl is then reformed and a
double bond in the
benzene ring attacks the carbon atom in the pronated imine cation. Water then acts as a
base and deprotonates the
α-carbon, reforming the aromatic ring and pushing electrons onto oxygen. The oxygen, which now has a negative
formal charge, then attacks a hydrogen on the
hydronium, resulting in an α-aminobenzylphenol, with water as the only byproduct. ==Betti Base==