For any given Caccioppoli set E \subset \R ^n there exist two naturally associated analytic quantities: the vector-valued
Radon measure D\chi_E and its
total variation measure |D\chi_E|. Given that : P(E, \Omega) = |D\chi_E|(\Omega) is the perimeter within any open set \Omega, one should expect that D\chi_E alone should somehow account for the perimeter of E.
The topological boundary It is natural to try to understand the relationship between the objects D\chi_E, |D\chi_E|, and the
topological boundary \partial E. There is an elementary lemma that guarantees that the
support (in the sense of
distributions) of D\chi_E, and therefore also |D\chi_E|, is always
contained in \partial E:
Lemma. The support of the vector-valued Radon measure D\chi_E is a
subset of the
topological boundary \partial E of E.
Proof. To see this choose x_0 \notin\partial E: then x_0 belongs to the
open set \R ^n\setminus\partial E and this implies that it belongs to an
open neighborhood A contained in the
interior of E or in the interior of \R^n\setminus E. Let \phi \in C^1_c(A; \R ^n). If A\subseteq(\R^n \setminus E)^\circ=\R^n\setminus E^- where E^- is the
closure of E, then \chi_E(x)=0 for x \in A and : \int_\Omega \langle\boldsymbol{\phi}, D\chi_E(x)\rangle =- \int_A\chi_E(x) \, \operatorname{div}\boldsymbol{\phi}(x)\, \mathrm{d}x = 0 Likewise, if A\subseteq E^\circ then \chi_E(x)=1 for x \in A so :\int_\Omega \langle\boldsymbol{\phi}, D\chi_E(x)\rangle = -\int_A\operatorname{div} \boldsymbol{\phi}(x) \, \mathrm{d}x = 0 With \phi \in C^1_c(A, \R^n) arbitrary it follows that x_0 is outside the support of D\chi_E.
The reduced boundary The topological boundary \partial E turns out to be too crude for Caccioppoli sets because its
Hausdorff measure overcompensates for the perimeter P(E) defined above. Indeed, the Caccioppoli set :E = \{ (x,y) : 0 \leq x, y \leq 1 \} \cup \{ (x, 0) : -1 \leq x \leq 1 \} \subset \R^2 representing a square together with a line segment sticking out on the left has perimeter P(E) = 4, i.e. the extraneous line segment is ignored, while its topological boundary :\partial E = \{(x, 0) : -1 \leq x \leq 1 \} \cup \{(x, 1) : 0 \leq x \leq 1 \} \cup \{(x, y) : x \in \{0, 1\}, 0 \leq y \leq 1 \} has one-dimensional Hausdorff measure \mathcal{H}^1(\partial E) = 5. The "correct" boundary should therefore be a subset of \partial E. We define:
Definition 4. The
reduced boundary of a Caccioppoli set E \subset \R ^n is denoted by \partial^* E and is defined to be equal to be the collection of points x at which the limit: : \nu_E(x) := \lim_{\rho \downarrow 0} \frac{D\chi_E(B_\rho(x))}{|D\chi_E|(B_\rho(x))} \in \R^n exists and has length equal to one, i.e. |\nu_E(x)| = 1. One can remark that by the
Radon-Nikodym Theorem the reduced boundary \partial^* E is necessarily contained in the support of D\chi_E, which in turn is contained in the topological boundary \partial E as explained in the section above. That is: :\partial^* E \subseteq \operatorname{support} D\chi_E \subseteq \partial E The inclusions above are not necessarily equalities as the previous example shows. In that example, \partial E is the square with the segment sticking out, \operatorname{support} D\chi_E is the square, and \partial^* E is the square without its four corners.
De Giorgi's theorem For convenience, in this section we treat only the case where \Omega = \R ^n, i.e. the set E has (globally) finite perimeter. De Giorgi's theorem provides geometric intuition for the notion of reduced boundaries and confirms that it is the more natural definition for Caccioppoli sets by showing : P(E) \left( = \int |D\chi_E| \right) = \mathcal{H}^{n-1}(\partial^* E) i.e. that its
Hausdorff measure equals the perimeter of the set. The statement of the theorem is quite long because it interrelates various geometric notions in one fell swoop.
Theorem. Suppose E \subset \R^n is a Caccioppoli set. Then at each point x of the reduced boundary \partial^* E there exists a multiplicity one
approximate tangent space T_x of |D\chi_E|, i.e. a codimension-1 subspace T_x of \R ^n such that : \lim_{\lambda \downarrow 0} \int_{\R^n} f(\lambda^{-1}(z-x)) |D\chi_E|(z) = \int_{T_x} f(y) \, d\mathcal{H}^{n-1}(y) for every continuous, compactly supported f : \R ^n \to \R . In fact the subspace T_x is the
orthogonal complement of the unit vector :\nu_E(x) = \lim_{\rho \downarrow 0} \frac{D\chi_E(B_\rho(x))}{|D\chi_E|(B_\rho(x))} \in \R ^n defined previously. This unit vector also satisfies :\lim_{\lambda \downarrow 0} \left \{ \lambda^{-1}(z - x) : z \in E \right \} \to \left \{ y \in \R^n : y \cdot \nu_E(x) > 0 \right \} locally in L^1, so it is interpreted as an approximate inward pointing
unit normal vector to the reduced boundary \partial^* E. Finally, \partial^* E is (n-1)-
rectifiable and the restriction of (n-1)-dimensional
Hausdorff measure \mathcal{H}^{n-1} to \partial^* E is |D\chi_E|, i.e. :|D\chi_E|(A) = \mathcal{H}^{n-1}(A \cap \partial^* E) for all Borel sets A \subset \R^n. In other words, up to \mathcal{H}^{n-1}-measure zero the reduced boundary \partial^* E is the smallest set on which D\chi_E is supported. == Applications ==