By definition, a set S is
countable if there exists a
bijection between S and a subset of the
natural numbers \N=\{0,1,2,\dots\}. For example, define the correspondence a \leftrightarrow 1,\ b \leftrightarrow 2,\ c \leftrightarrow 3 Since every element of S=\{a,b,c\} is paired with
precisely one element of \{1,2,3\},
and vice versa, this defines a bijection, and shows that S is countable. Similarly we can show all finite sets to be countable. As for the case of infinite sets, a set S is countably infinite if there is a
bijection between S and all of \N. As examples, consider the sets A=\{1,2,3,\dots\}, the set of positive
integers, and B=\{0,2,4,6,\dots\}, the set of even integers. We can show these sets are countably infinite by exhibiting a bijection to the natural numbers. This can be achieved using the assignments n \leftrightarrow n+1 and n \leftrightarrow 2n, so that \begin{matrix} 0 \leftrightarrow 1, & 1 \leftrightarrow 2, & 2 \leftrightarrow 3, & 3 \leftrightarrow 4, & 4 \leftrightarrow 5, & \ldots \\[6pt] 0 \leftrightarrow 0, & 1 \leftrightarrow 2, & 2 \leftrightarrow 4, & 3 \leftrightarrow 6, & 4 \leftrightarrow 8, & \ldots \end{matrix} Every countably infinite set is countable, and every infinite countable set is countably infinite. Furthermore, any subset of the natural numbers is countable, and more generally: The set of all
ordered pairs of natural numbers (the
Cartesian product of two sets of natural numbers, \N\times\N) is countably infinite, as can be seen by following a path like the one in the picture: assigns one natural number (blue) to each pair of natural numbers (horizontal,vertical coordinates). The resulting
mapping proceeds as follows: 0 \leftrightarrow (0, 0), 1 \leftrightarrow (1, 0), 2 \leftrightarrow (0, 1), 3 \leftrightarrow (2, 0), 4 \leftrightarrow (1, 1), 5 \leftrightarrow (0, 2), 6 \leftrightarrow (3, 0), \ldots This mapping covers all such ordered pairs. This form of triangular mapping
recursively generalizes to n-
tuples of natural numbers, i.e., (a_1,a_2,a_3,\dots,a_n) where a_i and n are natural numbers, by repeatedly mapping the first two elements of an n-tuple to a natural number. For example, (0, 2, 3) can be written as ((0, 2), 3). Then (0, 2) maps to 5 so ((0, 2), 3) maps to (5, 3), then (5, 3) maps to 39. Since a different 2-tuple, that is a pair such as (a,b), maps to a different natural number, a difference between two n-tuples by a single element is enough to ensure the n-tuples being mapped to different natural numbers. So, an injection from the set of n-tuples to the set of natural numbers \N is proved. For the set of n-tuples made by the Cartesian product of finitely many different sets, each element in each tuple has the correspondence to a natural number, so every tuple can be written in natural numbers then the same logic is applied to prove the theorem. }} The set of all
integers \Z and the set of all
rational numbers \Q may intuitively seem much bigger than \N. But looks can be deceiving. If a pair is treated as the
numerator and
denominator of a
vulgar fraction (a fraction in the form of a/b where a and b\neq 0 are integers), then for every positive fraction, we can come up with a distinct natural number corresponding to it. This representation also includes the natural numbers, since every natural number n is also a fraction n/1. So we can conclude that there are exactly as many positive rational numbers as there are positive integers. This is also true for all rational numbers, as can be seen below. In a similar manner, the set of
algebraic numbers is countable.{{efn|1=
Proof: Per definition, every algebraic number (including complex numbers) is a root of a polynomial with integer coefficients. Given an algebraic number \alpha, let a_0x^0 + a_1 x^1 + a_2 x^2 + \cdots + a_n x^n be a polynomial with integer coefficients such that \alpha is the k-th root of the polynomial, where the roots are sorted by absolute value from small to big, then sorted by argument from small to big. We can define an injection (i. e. one-to-one) function f:\mathbb{A}\to\Q given by f(\alpha) = 2^{k-1} \cdot 3^{a_0} \cdot 5^{a_1} \cdot 7^{a_2} \cdots {p_{n+2}}^{a_n}, where p_n is the n-th
prime.}} Sometimes more than one mapping is useful: if a set A to be shown as countable is one-to-one mapped (injection) to another set B, then A is proved as countable if B is one-to-one mapped to the set of natural numbers. For example, the set of positive
rational numbers can easily be one-to-one mapped to the set of natural number pairs (2-tuples) because p/q maps to (p,q). Since the set of natural number pairs is one-to-one mapped (actually one-to-one correspondence or bijection) to the set of natural numbers as shown above, the positive rational number set is proved as countable. {{math theorem G : I \times \mathbf{N} \to \bigcup_{i \in I} A_i, given by G(i,m)=g_i(m) is a surjection. Since I\times \N is countable, the union \bigcup_{i \in I} A_i is countable. }} }} With the foresight of knowing that there are uncountable sets, we can wonder whether or not this last result can be pushed any further. The answer is "yes" and "no", we can extend it, but we need to assume a new axiom to do so. For example, given countable sets \textbf{a},\textbf{b},\textbf{c},\dots, we first assign each element of each set a tuple, then we assign each tuple an index using a variant of the triangular enumeration we saw above: \begin{array}{ c|c|c } \text{Index} & \text{Tuple} & \text {Element} \\ \hline 0 & (0,0) & \textbf{a}_0 \\ 1 & (0,1) & \textbf{a}_1 \\ 2 & (1,0) & \textbf{b}_0 \\ 3 & (0,2) & \textbf{a}_2 \\ 4 & (1,1) & \textbf{b}_1 \\ 5 & (2,0) & \textbf{c}_0 \\ 6 & (0,3) & \textbf{a}_3 \\ 7 & (1,2) & \textbf{b}_2 \\ 8 & (2,1) & \textbf{c}_1 \\ 9 & (3,0) & \textbf{d}_0 \\ 10 & (0,4) & \textbf{a}_4 \\ \vdots & & \end{array} We need the
axiom of countable choice to index
all the sets \textbf{a},\textbf{b},\textbf{c},\dots simultaneously. This set is the union of the length-1 sequences, the length-2 sequences, the length-3 sequences, and so on, each of which is a countable set (finite Cartesian product). Thus the set is a countable union of countable sets, which is countable by the previous theorem. The elements of any finite subset can be ordered into a finite sequence. There are only countably many finite sequences, so also there are only countably many finite subsets. These follow from the definitions of countable set as injective / surjective functions. '''
Cantor's theorem''' asserts that if A is a set and \mathcal{P}(A) is its
power set, i.e. the set of all subsets of A, then there is no surjective function from A to \mathcal{P}(A). A proof is given in the article
Cantor's theorem. As an immediate consequence of this and the Basic Theorem above we have: For an elaboration of this result see
Cantor's diagonal argument. The set of
real numbers is uncountable, and so is the set of all infinite
sequences of natural numbers. ==Minimal model of set theory is countable==