The following systems generate continuous curves.
Cesàro curves .
Cesàro curves, also known as
Cesàro–Faber curves or
Lévy C curves, are De Rham curves generated by
affine transformations conserving
orientation, with fixed points p_0=0 and p_1=1. Because of these constraints, Cesàro curves are uniquely determined by a
complex number a such that |a| and |1-a|. The contraction mappings d_0 and d_1 are then defined as complex functions in the
complex plane by: :d_0(z) = az :d_1(z) = a + (1-a)z. For the value of a=(1+i)/2, the resulting curve is the
Lévy C curve.
Koch–Peano curves . In a similar way, we can define the Koch–Peano family of curves as the set of De Rham curves generated by affine transformations reversing orientation, with fixed points p_0=0 and p_1=1. These mappings are expressed in the complex plane as a function of \overline{z}, the
complex conjugate of z: :d_0(z) = a\overline{z} :d_1(z) = a + (1-a)\overline{z}. The name of the family comes from its two most famous members. The
Koch curve is obtained by setting: :a_\text{Koch}=\frac{1}{2} + i\frac{\sqrt{3}}{6}, while the
Peano curve corresponds to: :a_\text{Peano}=\frac{(1+i)}{2}. The de Rham curve for a=(1+ib)/2 for values of b just less than one visually resembles the
Osgood curve. These two curves are closely related, but are not the same. The Osgood curve is obtained by repeated set subtraction, and thus is a
perfect set, much like the
Cantor set itself. The construction of the Osgood set asks that progressively smaller triangles to be subtracted, leaving behind a "fat" set of non-zero measure; the construction is analogous to the
fat Cantor set, which has a non-zero
measure. By contrast, the de Rham curve is not "fat"; the construction does not offer a way to "fatten up" the "line segments" that run "in between" the dyadic rationals.
General affine maps The Cesàro–Faber and Peano–Koch curves are both special cases of the general case of a pair of affine linear transformations on the complex plane. By fixing one endpoint of the curve at 0 and the other at 1, the general case is obtained by iterating on the two transforms :d_0=\begin{pmatrix} 1 & 0 & 0 \\ 0 & \alpha &\delta \\ 0 & \beta & \varepsilon \end{pmatrix} and :d_1=\begin{pmatrix} 1&0&0 \\ \alpha & 1-\alpha&\zeta \\ \beta&-\beta&\eta \end{pmatrix}. Being
affine transforms, these transforms act on a point (u,v) of the 2-D plane by acting on the vector :\begin{pmatrix} 1 \\ u \\ v \end{pmatrix}. The midpoint of the curve can be seen to be located at (u,v)=(\alpha,\beta); the other four parameters may be varied to create a large variety of curves. The
blancmange curve of parameter w can be obtained by setting \alpha=\beta=1/2, \delta=\zeta=0 and \varepsilon=\eta=w. That is: :d_0=\begin{pmatrix} 1&0&0 \\ 0 & 1/2&0 \\ 0&1/2&w \end{pmatrix} and :d_1=\begin{pmatrix} 1&0&0 \\ 1/2 & 1/2&0 \\ 1/2&-1/2&w \end{pmatrix}. Since the blancmange curve for parameter w=1/4 is a parabola of the equation f(x)=4x(1-x), this illustrates the fact that on some occasions, de Rham curves can be smooth.
Minkowski's question mark function Minkowski's question mark function is generated by the pair of maps :d_0(z) = \frac{z}{z+1} and :d_1(z)= \frac{1}{2-z}. ==Non-examples==