The field of complex numbers \Complex is an extension field of the field of
real numbers \R, and \R in turn is an extension field of the field of rational numbers \Q. Clearly then, \Complex/\Q is also a field extension. We have [\Complex:\R] =2 because \{1, i\} is a basis, so the extension \Complex/\R is finite. This is a simple extension because \Complex = \R(i). [\R:\Q] =\mathfrak c (the
cardinality of the continuum), so this extension is infinite. The field :\Q(\sqrt{2}) = \left \{ a + b\sqrt{2} \mid a,b \in \Q \right \}, is an extension field of \Q, also clearly a simple extension. The degree is 2 because \left\{1, \sqrt{2}\right\} can serve as a basis. The field :\begin{align} \Q\left(\sqrt{2}, \sqrt{3}\right) &= \Q \left(\sqrt{2}\right) \left(\sqrt{3}\right) \\ &= \left\{ a+b\sqrt{3} \mid a,b \in \Q\left(\sqrt{2}\right) \right\} \\ &= \left\{ a + b \sqrt{2} + c\sqrt{3} + d\sqrt{6} \mid a,b,c, d \in \Q \right\}, \end{align} is an extension field of both \Q(\sqrt{2}) and \Q, of degree 2 and 4 respectively. It is also a simple extension, as one can show that :\begin{align} \Q(\sqrt{2}, \sqrt{3}) &= \Q (\sqrt{2} + \sqrt{3}) \\ &= \left \{ a + b (\sqrt{2} + \sqrt{3}) + c (\sqrt{2} + \sqrt{3})^2 + d(\sqrt{2} + \sqrt{3})^3 \mid a,b,c, d \in \Q\right\}. \end{align} Finite extensions of \Q are also called
algebraic number fields and are important in
number theory. Another extension field of the rationals, which is also important in number theory, although not a finite extension, is the field of
p-adic numbers \Q_p for a prime number
p. It is common to construct an extension field of a given field
K as a
quotient ring of the
polynomial ring K[
X] in order to "create" a
root for a given polynomial
f(
X). Suppose for instance that
K does not contain any element
x with
x2 = −1. Then the polynomial X^2+1 is
irreducible in
K[
X], consequently the
ideal generated by this polynomial is
maximal, and L = K[X]/(X^2+1) is an extension field of
K which
does contain an element whose square is −1 (namely the
residue class of
X). By iterating the above construction, one can construct a
splitting field of any polynomial from
K[
X]. This is an extension field
L of
K in which the given polynomial splits into a product of linear factors. If
p is any
prime number and
n is a positive integer, there is a unique (up to isomorphism)
finite field GF(p^n) = \mathbb{F}_{p^n} with
pn elements; this is an extension field of the
prime field \operatorname{GF}(p) = \mathbb{F}_p = \Z/p\Z with
p elements. Given a field
K, we can consider the field
K(
X) of all
rational functions in the variable
X with coefficients in
K; the elements of
K(
X) are fractions of two
polynomials over
K, and indeed
K(
X) is the
field of fractions of the polynomial ring
K[
X]. This field of rational functions is an extension field of
K. This extension is infinite. Given a
Riemann surface M, the set of all
meromorphic functions defined on
M is a field, denoted by \Complex(M). It is a transcendental extension field of \Complex if we identify every complex number with the corresponding
constant function defined on
M. More generally, given an
algebraic variety V over some field
K, the
function field K(
V), consisting of the rational functions defined on
V, is an extension field of
K. == Algebraic extension ==