• An important ideal of the ring called the
Jacobson radical can be defined using maximal right (or maximal left) ideals. • If
R is a unital commutative ring with an ideal
m, then
k =
R/
m is a field if and only if
m is a maximal ideal. In that case,
R/
m is known as the
residue field. This fact can fail in non-unital rings. For example, 4\mathbb{Z} is a maximal ideal in 2\mathbb{Z} , but 2\mathbb{Z}/4\mathbb{Z} is not a field. • If
L is a maximal left ideal, then
R/
L is a simple left
R-module. Conversely in rings with unity, any simple left
R-module arises this way. Incidentally this shows that a collection of representatives of simple left
R-modules is actually a set since it can be put into correspondence with part of the set of maximal left ideals of
R. • '''
Krull's theorem'
(1929): Every nonzero unital ring has a maximal ideal. The result is also true if "ideal" is replaced with "right ideal" or "left ideal". More generally, it is true that every nonzero finitely generated module has a maximal submodule. Suppose I
is an ideal which is not R
(respectively, A
is a right ideal which is not R
). Then R
/I
is a ring with unity (respectively, R
/A
is a finitely generated module), and so the above theorems can be applied to the quotient to conclude that there is a maximal ideal (respectively, maximal right ideal) of R
containing I
(respectively, A''). • Krull's theorem can fail for rings without unity. A
radical ring, i.e. a ring in which the
Jacobson radical is the entire ring, has no simple modules and hence has no maximal right or left ideals. See
regular ideals for possible ways to circumvent this problem. • In a commutative ring with unity, every maximal ideal is a
prime ideal. The converse is not always true: for example, in any nonfield
integral domain the zero ideal is a prime ideal which is not maximal. Commutative rings in which prime ideals are maximal are known as
zero-dimensional rings, where the dimension used is the
Krull dimension. • If
k is a field, the preimage of a maximal ideal of a
finitely generated k-algebra under a
k-algebra homomorphism is a maximal ideal. However, the preimage of a maximal ideal of a unital commutative ring under a ring homomorphism is not necessarily maximal. For example, let f:\mathbb{Z}\to\mathbb{Q} be the
inclusion map and \mathfrak{n}=(0) in \mathbb{Q}. Then \mathfrak{n} is maximal in \mathbb{Q} but f^{-1}(\mathfrak{n})=(0) is not maximal in \mathbb{Z}. • A maximal ideal of a noncommutative ring might not be prime in the commutative sense. For example, let M_{n\times n}(\mathbb{Z}) be the ring of all n\times n matrices over \mathbb{Z}. This ring has a maximal ideal M_{n\times n}(p\mathbb{Z}) for any prime p, but this is not a prime ideal since (in the case n=2)A=\text{diag}(1,p) and B=\text{diag}(p,1) are not in M_{n\times n}(p\mathbb{Z}), but AB=pI_2\in M_{n\times n}(p\mathbb{Z}). However, maximal ideals of noncommutative rings
are prime in the
generalized sense below. ==Generalization==