As a
function of a complex variable, z \mapsto w = \operatorname{gd} z
conformally maps the infinite strip \left|\operatorname{Im}z\right| \leq \tfrac12\pi to the infinite strip \left|\operatorname{Re}w\right| \leq \tfrac12\pi, while w \mapsto z = \operatorname{gd}^{-1} w conformally maps the infinite strip \left|\operatorname{Re}w\right| \leq \tfrac12\pi to the infinite strip \left|\operatorname{Im}z\right| \leq \tfrac12\pi.
Analytically continued by
reflections to the whole complex plane, z \mapsto w = \operatorname{gd} z is a periodic function of period 2\pi i which sends any infinite strip of "height" 2\pi i onto the strip -\pi Likewise, extended to the whole complex plane, w \mapsto z = \operatorname{gd}^{-1} w is a periodic function of period 2\pi which sends any infinite strip of "width" 2\pi onto the strip -\pi For all points in the complex plane, these functions can be correctly written as: :\begin{aligned} \operatorname{gd} z &= {2\arctan}\bigl(\tanh\tfrac12 z \,\bigr), \\[5mu] \operatorname{gd}^{-1} w &= {2\operatorname{artanh}}\bigl(\tan\tfrac12 w \,\bigr). \end{aligned} For the \operatorname{gd} and \operatorname{gd}^{-1} functions to remain invertible with these extended domains, we might consider each to be a
multivalued function (perhaps \operatorname{Gd} and \operatorname{Gd}^{-1}, with \operatorname{gd} and \operatorname{gd}^{-1} the
principal branch) or consider their domains and codomains as
Riemann surfaces. If u + iv = \operatorname{gd}(x + iy), then the real and imaginary components u and v can be found by: : \tan u = \frac{\sinh x}{\cos y}, \quad \tanh v = \frac{\sin y}{\cosh x}. (In practical implementation, make sure to use the
2-argument arctangent, {{nobr|u = \operatorname{atan2}(\sinh x, \cos y).)}} Likewise, if x + iy = \operatorname{gd}^{-1}(u + iv), then components x and y can be found by: : \tanh x = \frac{\sin u}{\cosh v}, \quad \tan y = \frac{\sinh v}{\cos u}. Multiplying these together reveals the additional identity :\begin{aligned} \operatorname{gd} iz &= i \operatorname{gd}^{-1} z, \\[5mu] \operatorname{gd}^{-1} iz &= i \operatorname{gd} z. \end{aligned} The functions are both
odd and they commute with
complex conjugation. That is, a reflection across the real or imaginary axis in the domain results in the same reflection in the
codomain: :\begin{aligned} \operatorname{gd} (-z) &= -\operatorname{gd} z, &\quad \operatorname{gd} \bar z &= \overline{\operatorname{gd} z}, &\quad \operatorname{gd} (-\bar z) &= -\overline{\operatorname{gd} z}, \\[5mu] \operatorname{gd}^{-1} (-z) &= -\operatorname{gd}^{-1} z, &\quad \operatorname{gd}^{-1} \bar z &= \overline{\operatorname{gd}^{-1} z}, &\quad \operatorname{gd}^{-1} (-\bar z) &= -\overline{\operatorname{gd}^{-1} z}. \end{aligned} The functions are
periodic, with periods 2\pi i and 2\pi: :\begin{aligned} \operatorname{gd} (z + 2\pi i) &= \operatorname{gd} z, \\[5mu] \operatorname{gd}^{-1} (z + 2\pi) &= \operatorname{gd}^{-1} z. \end{aligned} A translation in the domain of \operatorname{gd} by \pm\pi i results in a half-turn rotation and translation in the codomain by one of \pm\pi, and vice versa for \operatorname{gd}^{-1}\colon :\begin{aligned} \operatorname{gd} ({\pm \pi i} + z) &= \begin{cases} \pi - \operatorname{gd} z \quad &\mbox{if }\ \ \operatorname{Re} z \geq 0, \\[5mu] -\pi - \operatorname{gd} z \quad &\mbox{if }\ \ \operatorname{Re} z A reflection in the domain of \operatorname{gd} across either of the lines x \pm \tfrac12\pi i results in a reflection in the codomain across one of the lines \pm \tfrac12\pi + yi, and vice versa for \operatorname{gd}^{-1}\colon :\begin{aligned} \operatorname{gd} ({\pm \pi i} + \bar z) &= \begin{cases} \pi - \overline{\operatorname{gd} z} \quad &\mbox{if }\ \ \operatorname{Re} z \geq 0, \\[5mu] -\pi - \overline{\operatorname{gd} z} \quad &\mbox{if }\ \ \operatorname{Re} z This is related to the identity : \tanh\tfrac12 ({\pi i} \pm z) = \tan\tfrac12 ({\pi} \mp \operatorname{gd} z).
Specific values A few specific values (where \infty indicates the limit at one end of the infinite strip): :\begin{align} \operatorname{gd}(0) &= 0, &\quad {\operatorname{gd}}\bigl({\pm {\log}\bigl(2 + \sqrt3\bigr)}\bigr) &= \pm \tfrac13\pi, \\[5mu] \operatorname{gd}(\pi i) &= \pi, &\quad {\operatorname{gd}}\bigl({\pm \tfrac13}\pi i\bigr) &= \pm {\log}\bigl(2 + \sqrt3\bigr)i, \\[5mu] \operatorname{gd}({\pm \infty}) &= \pm\tfrac12\pi, &\quad {\operatorname{gd}}\bigl({\pm {\log}\bigl(1 + \sqrt2\bigr)}\bigr) &= \pm \tfrac14\pi, \\[5mu] {\operatorname{gd}}\bigl({\pm \tfrac12}\pi i\bigr) &= \pm \infty i, &\quad {\operatorname{gd}}\bigl({\pm \tfrac14}\pi i\bigr) &= \pm {\log}\bigl(1 + \sqrt2\bigr)i, \\[5mu] && {\operatorname{gd}}\bigl({\log}\bigl(1 + \sqrt2\bigr) \pm \tfrac12\pi i\bigr) &= \tfrac12\pi \pm {\log}\bigl(1 + \sqrt2\bigr)i, \\[5mu] && {\operatorname{gd}}\bigl({-\log}\bigl(1 + \sqrt2\bigr) \pm \tfrac12\pi i\bigr) &= -\tfrac12\pi \pm {\log}\bigl(1 + \sqrt2\bigr)i. \end{align} ==Derivatives==