• The ring of
p-adic integers \Z_p is obtained by completing the ring \Z of integers at the ideal (
p). • Let
R =
K[
x1,...,
xn] be the
polynomial ring in
n variables over a field
K and \mathfrak{m}=(x_1,\ldots,x_n) be the maximal ideal generated by the variables. Then the completion \widehat{R}_{\mathfrak{m}} is the ring
Kx1,...,xn of
formal power series in
n variables over
K. • Given a noetherian ring R and an ideal I = (f_1,\ldots, f_n), the I-adic completion of R is an image of a formal power series ring, specifically, the image of the surjection ::\begin{cases} R
x_1, \ldots, x_n \to \widehat{R}_I \\ x_i \mapsto f_i \end{cases} :The kernel is the ideal (x_1 - f_1, \ldots, x_n - f_n). Completions can also be used to analyze the local structure of
singularities of a
scheme. For example, the affine schemes associated to \Complex[x,y]/(xy) and the nodal cubic
plane curve \Complex[x,y]/(y^2 - x^2(1+x)) have similar looking singularities at the origin when viewing their graphs (both look like a plus sign). Notice that in the second case, any
Zariski neighborhood of the origin is still an irreducible curve. If we use completions, then we are looking at a "small enough" neighborhood where the node has two components. Taking the localizations of these rings along the ideal (x,y) and completing gives \Complex
x,y/(xy) and \Complex
x,y/((y+u)(y-u)) respectively, where u is the formal square root of x^2(1+x) in \Complex
x,y. More explicitly, the power series: :u = x\sqrt{1+x} = \sum_{n=0}^\infty \frac{(-1)^n(2n)!}{(1-2n)(n!)^2(4^n)}x^{n+1}. Since both rings are given by the intersection of two ideals generated by a homogeneous degree 1 polynomial, we can see algebraically that the singularities "look" the same. This is because such a scheme is the union of two non-equal linear subspaces of the affine plane. == Properties ==