The
Fourier transform of an
L1 function f on the
real line \mathbb R is defined as the
Lebesgue integral \hat f(\xi) = \int_{\mathbb R} f(x)e^{-2\pi i x\xi}dx. If f belongs to both L^1 and L^2, then the Plancherel theorem states that \hat f also belongs to L^2, and the Fourier transform is an
isometry with respect to the
L2 norm, which is to say that \int_{-\infty}^\infty |f(x)|^2 \, dx = \int_{-\infty}^\infty |\widehat{f}(\xi)|^2 \, d\xi This implies that the Fourier transform restricted to L^1(\mathbb{R}) \cap L^2(\mathbb{R}) has a unique extension to a
linear isometric map L^2(\mathbb{R}) \mapsto L^2(\mathbb{R}), sometimes called the Plancherel transform. This isometry is actually a
unitary map. In effect, this makes it possible to speak of Fourier transforms of
L2 functions. A proof of the theorem is available from
Rudin (1987, Chapter 9). The basic idea is to prove it for
Gaussian distributions, and then use density. But a standard Gaussian is transformed to itself under the Fourier transformation, and the theorem is trivial in that case. Finally, the standard transformation properties of the Fourier transform then imply Plancherel for all Gaussians. Plancherel's theorem remains valid as stated on
n-dimensional
Euclidean space \mathbb{R}^n. The theorem also holds more generally in
locally compact abelian groups. There is also a version of the Plancherel theorem which makes sense for non-commutative locally compact groups satisfying certain technical assumptions. This is the subject of
non-commutative harmonic analysis. Due to the
polarization identity, one can also apply Plancherel's theorem to the
L^2(\mathbb{R}) inner product of two functions. That is, if f(x) and g(x) are two L^2(\mathbb{R}) functions, and \mathcal P denotes the Plancherel transform, then \int_{-\infty}^\infty f(x)\overline{g(x)} \, dx = \int_{-\infty}^\infty (\mathcal P f)(\xi) \overline{(\mathcal P g)(\xi)} \, d\xi, and if f(x) and g(x) are furthermore L^1(\mathbb{R}) functions, then (\mathcal P f)(\xi) = \widehat{f}(\xi) = \int_{-\infty}^\infty f(x) e^{-2\pi i \xi x} \, dx , and (\mathcal P g)(\xi) = \widehat{g}(\xi) = \int_{-\infty}^\infty g(x) e^{-2\pi i \xi x} \, dx , so {{Equation box 1 ==Locally compact groups==