Subspaces and
products of Hausdorff spaces are Hausdorff, but
quotient spaces of Hausdorff spaces need not be Hausdorff. In fact,
every topological space can be realized as the quotient of some Hausdorff space. Hausdorff spaces are
T1, meaning that each
singleton is a closed set. Similarly, preregular spaces are
R0. Every Hausdorff space is a
Sober space although the converse is in general not true. Another property of Hausdorff spaces is that each
compact set is a closed set. For non-Hausdorff spaces, it can be that each compact set is a closed set (for example, the
cocountable topology on an uncountable set) or not (for example, the
cofinite topology on an infinite set and the
Sierpiński space). The definition of a Hausdorff space says that points can be separated by neighborhoods. It turns out that this implies something which is seemingly stronger: in a Hausdorff space every pair of disjoint compact sets can also be separated by neighborhoods, in other words there is a neighborhood of one set and a neighborhood of the other, such that the two neighborhoods are disjoint. This is an example of the general rule that compact sets often behave like points. Compactness conditions together with preregularity often imply stronger separation axioms. For example, any
locally compact preregular space is
completely regular.
Compact preregular spaces are
normal, meaning that they satisfy
Urysohn's lemma and the
Tietze extension theorem and have
partitions of unity subordinate to locally finite
open covers. The Hausdorff versions of these statements are: every locally compact Hausdorff space is
Tychonoff, and every compact Hausdorff space is normal Hausdorff. The following results are some technical properties regarding maps (
continuous and otherwise) to and from Hausdorff spaces. Let
f\colon X \to Y be a continuous function and suppose Y is Hausdorff. Then the
graph of
f, \{(x,f(x)) \mid x\in X\}, is a closed subset of
X \times Y. Let
f\colon X \to Y be a function and let \ker(f) \triangleq \{(x,x') \mid f(x) = f(x')\} be its
kernel regarded as a subspace of
X \times X. • If
f is continuous and
Y is Hausdorff then
\ker(f) is a closed set. • If
f is an
open surjection and
\ker(f) is a closed set then
Y is Hausdorff. • If
f is a continuous, open
surjection (i.e. an open quotient map) then
Y is Hausdorff
if and only if \ker(f) is a closed set. If
f, g \colon X \to Y are continuous maps and
Y is Hausdorff then the
equalizer \mbox{eq}(f,g) = \{x \mid f(x) = g(x)\} is a closed set in
X. It follows that if
Y is Hausdorff and
f and
g agree on a
dense subset of
X then
f = g. In other words, continuous functions into Hausdorff spaces are determined by their values on dense subsets. Let
f\colon X \to Y be a
closed surjection such that
f^{-1} (y) is
compact for all
y \in Y. Then if
X is Hausdorff so is
Y. Let
f\colon X \to Y be a
quotient map with
X a compact Hausdorff space. Then the following are equivalent: •
Y is Hausdorff. •
f is a
closed map. •
\ker(f) is a closed set. == Preregularity versus regularity ==