•
Sierpiński space is a simple example of a topology that is T0 but is not T1, and hence also not R0. • The
overlapping interval topology is a simple example of a topology that is T0 but is not T1. • Every
weakly Hausdorff space is T1 but the converse is not true in general. • The
cofinite topology on an
infinite set is a simple example of a topology that is T1 but is not
Hausdorff (T2). This follows since no two nonempty open sets of the cofinite topology are disjoint. Specifically, let X be the set of
integers, and define the
open sets O_A to be those subsets of X that contain all but a
finite subset A of X. Then given distinct integers x and y: :* the open set O_{\{ x \}} contains y but not x, and the open set O_{\{ y \}} contains x and not y; :* equivalently, every singleton set \{ x \} is the complement of the open set O_{\{ x \}}, so it is a closed set; :so the resulting space is T1 by each of the definitions above. This space is not T2, because the
intersection of any two open sets O_A and O_B is O_A \cap O_B = O_{A \cup B}, which is never empty. Alternatively, the set of even integers is
compact but not
closed, which would be impossible in a Hausdorff space. • The above example can be modified slightly to create the
double-pointed cofinite topology, which is an example of an R0 space that is neither T1 nor R1. Let X be the set of integers again, and using the definition of O_A from the previous example, define a
subbase of open sets G_x for any integer x to be G_x = O_{\{ x, x+1 \}} if x is an
even number, and G_x = O_{\{ x-1, x \}} if x is odd. Then the
basis of the topology are given by finite
intersections of the subbasic sets: given a finite set A,the open sets of X are ::U_A := \bigcap_{x \in A} G_x. :The resulting space is not T0 (and hence not T1), because the points x and x + 1 (for x even) are topologically indistinguishable; but otherwise it is essentially equivalent to the previous example. • The
Zariski topology on an
algebraic variety (over an
algebraically closed field) is T1. To see this, note that the singleton containing a point with
local coordinates \left(c_1, \ldots, c_n\right) is the
zero set of the
polynomials x_1 - c_1, \ldots, x_n - c_n. Thus, the point is closed. However, this example is well known as a space that is not
Hausdorff (T2). The Zariski topology is essentially an example of a cofinite topology. • The Zariski topology on a
commutative ring (that is, the prime
spectrum of a ring) is T0 but not, in general, T1. To see this, note that the closure of a one-point set is the set of all
prime ideals that contain the point (and thus the topology is T0). However, this closure is a
maximal ideal, and the only closed points are the maximal ideals, and are thus not contained in any of the open sets of the topology, and thus the space does not satisfy axiom T1. To be clear about this example: the Zariski topology for a commutative ring A is given as follows: the topological space is the set X of all
prime ideals of A. The
base of the topology is given by the open sets O_a of prime ideals that do contain a \in A. It is straightforward to verify that this indeed forms the basis: so O_a \cap O_b = O_{ab} and O_0 = \varnothing and O_1 = X. The closed sets of the Zariski topology are the sets of prime ideals that contain a. Notice how this example differs subtly from the cofinite topology example, above: the points in the topology are not closed, in general, whereas in a T1 space, points are always closed. • Every
totally disconnected space is T1, since every point is a
connected component and therefore closed. ==Generalisations to other kinds of spaces==