(\gamma) as a function of velocity.As velocity approaches zero, E_\text{rel} (the ordinate) becomes equal to E_0 = m c^2,but as v_e \to c , \gamma and E_\text{rel} go to infinity. One of the most important and familiar results of relativity is that the
relativistic mass of the
electron increases as m_\text{rel} = \gamma m_e = \frac{m_e}{\sqrt{1 - (v_e/c)^2}} where \gamma, m_e, v_e, c are the
Lorentz factor,
electron rest mass,
velocity of the electron, and
speed of light respectively. The figure at the right illustrates this relativistic effect as a function of velocity. This has an immediate implication on the
Bohr radius (a_0), which is given by a_0 = \frac{\hbar}{m_\text{e} c \alpha}, where \hbar is the
reduced Planck constant, and α is the
fine-structure constant (a relativistic correction for the
Bohr model). Bohr calculated that a
1s orbital electron of a hydrogen atom orbiting at the Bohr radius of 0.0529 nm travels at nearly 1/137 the speed of light. One can extend this to a larger element with an
atomic number Z by using the expression v \approx \frac{Zc}{137} for a 1s electron, where
v is its
radial velocity, i.e., its instantaneous speed tangent to the radius of the atom. For
gold with
Z = 79,
v ≈ 0.58
c, so the 1s electron will be moving at 58% of the speed of light. Substituting this in for
v/
c in the equation for the relativistic mass, one finds that
mrel = 1.22
me, and in turn putting this in for the Bohr radius above one finds that the radius shrinks by 22%. If one substitutes the "relativistic mass" into the equation for the Bohr radius it can be written a_\text{rel} = \frac{\hbar \sqrt{1 - (v_\text{e}/c)^2}}{m_\text{e} c \alpha}. It follows that \frac{a_\text{rel}}{a_0} = \sqrt{1 - (v_\text{e}/c)^2}. The ratio of the relativistic and nonrelativistic Bohr radii is simply 1 / \gamma , which as a function of the electron velocity is a circular arc. The relativistic radius reduces strongly as the electron velocity approaches c. When the Bohr treatment is extended to
hydrogenic atoms, the Bohr radius becomes r = \frac{n^2}{Z} a_0 = \frac{n^2 \hbar^2 4 \pi \varepsilon_0}{m_\text{e}Ze^2}, where n is the
principal quantum number, and
Z is an integer for the
atomic number. In the
Bohr model, the
angular momentum is given as mv_\text{e}r = n\hbar. Substituting into the equation above and solving for v_\text{e} gives \begin{align} r &= \frac{n^2 a_0}{Z} = \frac{n \hbar}{m v_\text{e}}, \\ v_\text{e} &= \frac{Z}{n^2 a_0} \frac{n \hbar}{m}, \\ \frac{v_\text{e}}{c} &= \frac{Z \alpha}{n} = \frac{Z e^2}{4 \pi \varepsilon_0 \hbar c n}. \end{align} Substituting the second-last equality into the expression for the Bohr ratio mentioned above gives \frac{a_\text{rel}}{a_0} = \sqrt{1 - (Z \alpha / n)^2} and since \alpha \approx 1 / 137, \frac{a_\text{rel}}{a_0} \approx \sqrt{1 - \left(\frac {Z}{137 n}\right)^2} At this point one can see that a low value of n and a high value of Z results in \frac{a_\text{rel}}{a_0} . This fits with intuition: electrons with lower principal quantum numbers will have a higher probability density of being nearer to the nucleus. A nucleus with a large charge will cause an electron to have a high velocity. A higher electron velocity means an increased electron relativistic mass, and as a result the electrons will be near the nucleus more of the time and thereby contract the radius for small principal quantum numbers. == Periodic table deviations ==