The cutoff frequency of an
electromagnetic waveguide is the lowest frequency for which a mode will propagate in it. In
fiber optics, it is more common to consider the
cutoff wavelength, the maximum
wavelength that will propagate in an
optical fiber or
waveguide. The cutoff frequency is found with the
characteristic equation of the
Helmholtz equation for electromagnetic waves, which is derived from the
electromagnetic wave equation by setting the longitudinal
wave number equal to zero and solving for the frequency. Thus, any exciting frequency lower than the cutoff frequency will attenuate, rather than propagate. The following derivation assumes lossless walls. The value of c, the
speed of light, should be taken to be the
group velocity of light in whatever material fills the waveguide. For a rectangular waveguide, the cutoff frequency is \omega_{c} = c \sqrt{\left(\frac{m \pi}{a}\right)^2 + \left(\frac{n \pi}{b}\right) ^2}, where m,n \ge 0 are the mode numbers for the rectangle's sides of length a and b respectively. For TE modes, m,n \ge 0 (but m = n = 0 is not allowed), while for TM modes m,n \ge 1 . The cutoff frequency of the TM01 mode (next higher from dominant mode TE11) in a waveguide of circular cross-section (the transverse-magnetic mode with no angular dependence and lowest radial dependence) is given by \omega_{c} = c \frac{\chi_{01}}{r} = c \frac{2.4048}{r}, where r is the radius of the waveguide, and \chi_{01} is the first root of J_{0}(r), the
Bessel function of the first kind of order 1. The dominant mode TE11 cutoff frequency is given by \omega_{c} = c \frac{\chi_{11}}{r} = c \frac{1.8412}{r} However, the dominant mode cutoff frequency can be reduced by the introduction of baffle inside the circular cross-section waveguide. For a
single-mode optical fiber, the cutoff wavelength is the wavelength at which the
normalized frequency is approximately equal to 2.405.
Mathematical analysis The starting point is the wave equation (which is derived from the
Maxwell equations), \left(\nabla^2-\frac{1}{c^2}\frac{\partial^2}{\partial{t}^2}\right)\psi(\mathbf{r},t)=0, which becomes a
Helmholtz equation by considering only functions of the form \psi(x,y,z,t) = \psi(x,y,z)e^{i \omega t}. Substituting and evaluating the time derivative gives \left(\nabla^2 + \frac{\omega^2}{c^2}\right) \psi(x,y,z) = 0. The function \psi here refers to whichever field (the electric field or the magnetic field) has no vector component in the longitudinal direction - the "transverse" field. It is a property of all the eigenmodes of the electromagnetic waveguide that at least one of the two fields is transverse. The
z axis is defined to be along the axis of the waveguide. The "longitudinal" derivative in the
Laplacian can further be reduced by considering only functions of the form \psi(x,y,z,t) = \psi(x,y)e^{i \left(\omega t - k_{z} z \right)}, where k_z is the longitudinal
wavenumber, resulting in \left(\nabla_{T}^2 - k_{z}^2 + \frac{\omega^2}{c^2}\right) \psi(x,y,z) = 0, where subscript T indicates a 2-dimensional transverse Laplacian. The final step depends on the geometry of the waveguide. The easiest geometry to solve is the rectangular waveguide. In that case, the remainder of the Laplacian can be evaluated to its characteristic equation by considering solutions of the form \psi(x,y,z,t) = \psi_{0}e^{i \left(\omega t - k_{z} z - k_{x} x - k_{y} y\right)}. Thus for the rectangular guide the Laplacian is evaluated, and we arrive at \frac{\omega^2}{c^2} = k_x^2 + k_y^2 + k_z^2 The transverse wavenumbers can be specified from the standing wave boundary conditions for a rectangular geometry cross-section with dimensions and : k_{x} = \frac{n \pi}{a}, k_{y} = \frac{m \pi}{b}, where and are the two integers representing a specific eigenmode. Performing the final substitution, we obtain \frac{\omega^2}{c^2} = \left(\frac{n \pi}{a}\right)^2 + \left(\frac{m \pi}{b}\right)^2 + k_{z}^2, which is the
dispersion relation in the rectangular waveguide. The cutoff frequency \omega_{c} is the critical frequency between propagation and attenuation, which corresponds to the frequency at which the longitudinal wavenumber k_{z} is zero. It is given by \omega_{c} = c \sqrt{\left(\frac{n \pi}{a}\right)^2 + \left(\frac{m \pi}{b}\right)^2} The wave equations are also valid below the cutoff frequency, where the longitudinal wave number is imaginary. In this case, the field decays exponentially along the waveguide axis and the wave is thus
evanescent. == See also ==