If is an algebraic function and \alpha is an
algebraic number then is also an algebraic number. The converse is not true: there are
entire transcendental functions such that is an algebraic number for any algebraic . For a given transcendental function the set of algebraic numbers giving algebraic results is called the
exceptional set of that function. Formally it is defined by: \mathcal{E}(f)=\left \{\alpha\in\overline{\Q}\,:\,f(\alpha)\in\overline{\Q} \right \}. In many instances the exceptional set is fairly small. For example, \mathcal{E}(\exp) = \{0\}; this was proved by
Lindemann in 1882 (see
Lindemann–Weierstrass theorem). In particular is transcendental. Also, since is algebraic we know that cannot be algebraic. Since is algebraic this implies that is a
transcendental number. In general, finding the exceptional set of a function is a difficult problem, but if it can be calculated then it can often lead to results in
transcendental number theory. Here are some other known exceptional sets: • Klein's
j-invariant \mathcal{E}(j) = \left\{\alpha\in\mathcal{H}\,:\,[\Q(\alpha): \Q] = 2 \right\}, where is the
upper half-plane, and is the
degree of the
number field This result is due to
Theodor Schneider. • Exponential function in base 2: \mathcal{E}(2^x)=\Q,This result is a corollary of the
Gelfond–Schneider theorem, which states that if \alpha \neq 0,1 is algebraic, and \beta is algebraic and irrational then \alpha^\beta is transcendental. Thus the function could be replaced by for any algebraic not equal to 0 or 1. Indeed, we have: \mathcal{E}(x^x) = \mathcal{E}\left(x^{\frac{1}{x}}\right)=\Q\setminus\{0\}. • A consequence of
Schanuel's conjecture in transcendental number theory would be that \mathcal{E}\left(e^{e^x}\right)=\emptyset. • A function with empty exceptional set that does not require assuming Schanuel's conjecture is f(x) = \exp(1 + \pi x). While calculating the exceptional set for a given function is not easy, it is known that given
any subset of the algebraic numbers, say , there is a transcendental function whose exceptional set is . The subset does not need to be proper, meaning that can be the set of algebraic numbers. This directly implies that there exist transcendental functions that produce transcendental numbers only when given transcendental numbers.
Alex Wilkie also proved that there exist transcendental functions for which
first-order-logic proofs about their transcendence do not exist by providing an exemplary
analytic function. ==Dimensional analysis==