Existence The theory of the Beltrami equation can be extended to measurable Beltrami coefficients
μ. For simplicity only a special class of
μ will be considered—adequate for most applications—namely those functions which are smooth an open set Ω (the regular set) with complement Λ a closed set of measure zero (the singular set). Thus Λ is a closed set that is contained in open sets of arbitrarily small area. For measurable Beltrami coefficients
μ with compact support in |
z|
n of compact support with 0 ≤ φ
n ≤ 1, equal to 1 on a neighborhood of Λ and 0 off a slightly larger neighbourhood, shrinking to Λ as
n increases. Set :\displaystyle{\mu_n=(1-\varphi_n)\cdot\mu.} The
μn are smooth with compact support in |
z| \displaystyle{\|\mu_n\|_\infty \le \|\mu\|_\infty.} The
μn tend to
μ in any
Lp norm with
p n of the Beltrami equations and their inverses
gn satisfy uniform Hölder estimates. They are therefore
equicontinuous on any compact subset of
C; they are even holomorphic for |
z| >
R. So by the
Arzelà–Ascoli theorem, passing to a subsequence if necessary, it can be assumed that both
fn and
gn converge uniformly on compacta to
f and
g. The limits will satisfy the same Hölder estimates and be holomorphic for |
z| >
R. The relations
fn\circ
gn = id =
gn\circ
fn imply that in the limit
f\circ
g = id =
g\circ
f, so that
f and
g are homeomorphisms. • The limits
f and
g are weakly differentiable. In fact let ::\displaystyle{u_n=\partial_{\overline{z}} f_n,\,\, v_n =\partial_z f_n-1.} :These lie in Lp and are uniformly bounded: ::\displaystyle{\|u_n\|_p,\,\, \|v_n\|_p \le {\|\mu_n\|_p\over 1 - \|\mu_n\|_\infty}.} :Passing to a subsequence if necessary, it can be assumed that the sequences have weak limits
u and
v in Lp. These are the distributional derivatives of
f(
z) –
z, since if ψ is smooth of compact support ::\displaystyle{\iint u \cdot \psi =\lim\iint u_n\cdot \psi =-\lim \iint f_n \cdot \partial_{\overline {z}} \psi = -\iint f\cdot \partial_{\overline {z}} \psi,} :and similarly for
v. A similar argument applies for the
g using the fact that Beltrami coefficients of the
gn are supported in a fixed closed disk. •
f satisfies the Beltrami equation with Beltrami coefficient
μ. In fact the relation
u =
μ ⋅
v +
μ follows by continuity from the relation
un =
μn ⋅
vn +
μn. It suffices to show that
μn ⋅
vn tends weakly to
μ ⋅
v. The difference can be written ::\displaystyle{\mu v -\mu_n v_n= \mu(v-v_n) +(\mu-\mu_n)v_n.} :The first term tends weakly to 0, while the second term equals
μ φn vn. The terms are uniformly bounded in
Lp, so to check weak convergence to 0 it enough to check inner products with a dense subset of
L2. The inner products with functions of compact support in Ω are zero for
n sufficiently large. •
f carries closed sets of measure zero onto closed sets of measure zero. It suffices to check this for a compact set
K of measure zero. If
U is a bounded open set containing
K and
J denotes the Jacobian of a function, then :: \begin{align} A(f_n(U)) & = \iint_U J(f_n)\, dx\, dy =\iint_U |\partial_z f_n|^2 -|\partial_{\overline{z}}f_n|^2\, dx\,dy \\[4pt] & \le \iint_U |\partial_z f_n|^2\, dx\, dy\le \|\partial_z f_n|_U\|_p^2 \,A(U)^{1-2/p}. \end{align} :Thus if
A(
U) is small, so is
A(
fn(
U)). On the other hand
fn(
U) eventually contains
f(
K), for applying the inverse
gn,
U eventually contains
gn \circ
f (
K) since
gn \circ
f tends uniformly to the identity on compacta. Hence
f(
K) has measure zero. •
f is smooth on the regular set Ω of
μ. This follows from the elliptic regularity results in the
L2 theory. •
f has non-vanishing Jacobian there. In particular
fz ≠ 0 on Ω. In fact for
z0 in Ω, if
n is large enough ::\displaystyle{\partial_{\overline{z}} (f\circ g_n) = 0} :near
z1 =
fn(
z0). So
h =
f \circ
gn is holomorphic near
z1. Since it is locally a homeomorphism,
h ' (
z1) ≠ 0. Since
f =
h \circ
fn. it follows that the Jacobian of
f is non-zero at
z0. On the other hand
J(
f) = |
fz|2 (1 − |μ|2), so
fz ≠ 0 at
z0. •
g satisfies the Beltrami equation with Beltrami coefficient ::\displaystyle{\mu^\prime(f(z))=-{f_z\over \overline{f_z}}\cdot \mu(z)} :or equivalently ::\displaystyle{\mu^\prime(w) =-{\overline{g_w}\over g_w} \cdot \mu(g(w))} :on the regular set Ω ' =
f(Ω), with corresponding singular set Λ ' =
f(Λ). •
g satisfies the Beltrami equation for
μ′. In fact
g has weak distributional derivatives in 1 + L
p and L
p. Pairing with smooth functions of compact support in Ω, these derivatives coincide with the actual derivatives at points of Ω. Since Λ has measure zero, the distributional derivatives equal the actual derivatives in
Lp. Thus
g satisfies Beltrami's equation since the actual derivatives do. • If
f* and
f are solutions constructed as above for
μ* and
μ then
f* \circ
f−1 satisfies the Beltrami equation for ::\displaystyle \nu(f(z))={f_z\over \overline{f_z}} \, {\mu^* - \mu\over 1-\overline{\mu} \mu^*}, :defined on Ω ∩ Ω*. The weak derivatives of
f* \circ
f−1 are given by the actual derivatives on Ω ∩ Ω*. In fact this follows by approximating
f* and
g =
f−1 by
f*
n and
gn. The derivatives are uniformly bounded in 1 + L
p and L
p, so as before weak limits give the distributional derivatives of
f* \circ
f−1. Pairing with smooth functions of compact support in Ω ∩ Ω*, these agree with the usual derivatives. So the distributional derivatives are given by the usual derivatives off Λ ∪ Λ*, a set of measure zero. This establishes the
existence of homeomorphic solutions of Beltrami's equation in the case of Beltrami coefficients of compact support. It also shows that the inverse homeomorphisms and composed homeomorphisms satisfy Beltrami equations and that all computations can be performed by restricting to regular sets. If the support is not compact the same trick used in the smooth case can be used to construct a solution in terms of two homeomorphisms associated to compactly supported Beltrami coefficients. Note that, because of the assumptions on the Beltrami coefficient, a Möbius transformation of the extended complex plane can be applied to make the singular set of the Beltrami coefficient compact. In that case one of the homeomorphisms can be chosen to be a diffeomorphism.
Uniqueness There are several proofs of the uniqueness of solutions of the Beltrami equation with a given Beltrami coefficient. Since applying a Möbius transformation of the complex plane to any solution gives another solution, solutions can be normalised so that they fix 0, 1 and ∞. The method of solution of the Beltrami equation using the Beurling transform also provides a proof of uniqueness for coefficients of compact support
μ and for which the distributional derivatives are in 1 + L
p and L
p. The relations :\displaystyle (P\psi)_{\overline{z}} = \psi, \,\, \, (P\psi)_{z} = T\psi for smooth functions ψ of compact support are also valid in the distributional sense for L
p functions
h since they can be written as L
p of ψ
n's. If
f is a solution of the Beltrami equation with
f(0) = 0 and
fz - 1 in L
p then :\displaystyle{F=f-P(f_{\overline{z}})} satisfies :\displaystyle{\partial_{\overline{z}}F =0.} So
F is weakly holomorphic. Applying Weyl's lemma it is possible to conclude that there exists a holomorphic function
G that is equal to
F almost everywhere. Abusing notation redefine
F:=G. The conditions
F '(z) − 1 lies in L
p and
F(0) = 0 force
F(
z) =
z. Hence :\displaystyle{P(f_{\overline{z}}) = f(z) + z} and so differentiating :\displaystyle{f_z=T(\mu f_z) + 1.} If
g is another solution then :\displaystyle{f_z-g_z=T(\mu(f_z-g_z)).} Since
Tμ has operator norm on L
p less than 1, this forces :\displaystyle{f_z=g_z.} But then from the Beltrami equation :\displaystyle{f_{\overline{z}}=g_{\overline{z}}.} Hence
f −
g is both holomorphic and antiholomorphic, so a constant. Since
f(0) = 0 =
g(0), it follows that
f =
g. Note that since
f is holomorphic off the support of
μ and
f(∞) = ∞, the conditions that the derivatives are locally in L
p force :\displaystyle{f_z -1,\,\,f_{\overline{z}}\in L^p(\mathbf{C}).} For a general
f satisfying Beltrami's equation and with distributional derivatives locally in L
p, it can be assumed after applying a Möbius transformation that 0 is not in the singular set of the Beltrami coefficient
μ. If
g is a smooth diffeomorphism
g with Beltrami coefficient λ supported near 0, the Beltrami coefficient
ν for
f \circ
g−1 can be calculated directly using the change of variables formula for distributional derivatives: :\displaystyle \nu(g(z))= {g_z\over \overline{g_z}} \,{\mu -\lambda\over 1-\overline{\lambda}\mu}.
λ can be chosen so that ν vanishes near zero. Applying the map
z−1 results in a solution of Beltrami's equation with a Beltrami coefficient of compact support. The directional derivatives are still locally in L
p. The coefficient ν depends only on
μ,
λ and
g, so any two solutions of the original equation will produce solutions near 0 with distributional derivatives locally in
Lp and the same Beltrami coefficient. They are therefore equal. Hence the solutions of the original equation are equal. ==Uniformization of multiply connected planar domains==