Radiation pressure can be viewed as a consequence of the
conservation of momentum given the momentum attributed to electromagnetic radiation. That momentum can be equally well calculated on the basis of electromagnetic theory or from the combined momenta of a stream of photons, giving identical results as is shown below.
Physical origin Electromagnetic radiation consists of an
electric field E and a
magnetic field B related by: {{center| \mathbf{B} = \frac{\mathbf{n}\times\mathbf{E}}{c} }} where
n is the unit
vector directed along the propagation direction of the radiation, and
c is the
speed of light in vacuum. The fields are transverse and satisfy the relation \mathbf{E}\perp\mathbf{B}\perp\mathbf{n} . These properties are notably reflected in the
Panofsky–Phillips equations. When this
electromagnetic field reaches an
electric charge q initially at rest, the
electric field exerts a force (
F = q
E) on it, setting it into motion. Once the charge is in motion, it is also subject to a magnetic
force (\mathbf{F}=q\left(\mathbf{v}\times\mathbf{B}\right)) exerted by the magnetic component of the radiation. Since the velocity
v acquired by the charge is directed along
E, and the magnetic force is given by \mathbf{F}=q\left(\mathbf{v}\times\mathbf{B}\right) , it follows that this force is directed along
n. Moreover, one can note that the electric field exchanges
energy with the charge, while the magnetic field imparts
momentum to it. • The magnitude of the
power P transferred by the
electric field to the charge is given by: {{center| P=\mathbf{F}\cdot\mathbf{v} }} :which implies: • The magnitude of the
force F transmitted by the
magnetic field to the charge is, according to \mathbf{F}=q\left(\mathbf{v}\times\mathbf{B}\right) , given by: Since the magnitude of
B is related to that of
E by B = E/c, one obtains: {{center| F=\frac{qvE}{c} }} which implies that at any time
t, the instantaneous relation is: Integrating this relation with respect to time yields: where
p and
E are respectively the
momentum and
energy exchanged by the
electromagnetic field with the charge
q. This result shows that, in addition to transporting energy,
electromagnetic radiation also carries
momentum, and that the momentum exchanged with matter is always equal to the energy exchanged divided by the factor
c. Furthermore, since electromagnetic radiation carries a
momentum p, and since
p = m
v, it is also possible to assign it an equivalent
mass m, such that
m = p/v. As the propagation
velocity of the radiation is equal to the
speed of light c, the momentum of the radiation can be written as
p = mc. Using the previous result, this gives: {{center| mc=\frac{E}{c} }} That is, This equivalence between
energy and equivalent inertia of
electromagnetic radiation was notably studied by
Henri Poincaré in the early 1900s. The 1906 publication by
Albert Einstein on the relation
E = mc² is closely related to the above results (his 1905 work relies on the
relativistic Doppler effect).
Radiation pressure from momentum of an electromagnetic wave According to Maxwell's theory of electromagnetism, an electromagnetic wave carries momentum. Momentum will be transferred to any surface it strikes that absorbs or reflects the radiation. Consider the momentum transferred to a perfectly absorbing (black) surface. The energy flux (irradiance) of a plane wave is calculated using the
Poynting vector {{nowrap|\mathbf{S} = \mathbf{E} \times \mathbf{H}}}, which is the
cross product of the
electric field vector
E and the
magnetic field's auxiliary field vector (or
magnetizing field)
H. The magnitude, denoted by
S, divided by the
speed of light is the density of the linear momentum per unit area (pressure) of the electromagnetic field. So, dimensionally, the Poynting vector is , which is the speed of light, , times pressure, . That pressure is experienced as radiation pressure on the surface: P_\text{incident} = \frac{\langle S\rangle}{c} = \frac{I_f}{c} where P is pressure (usually in
pascals), I_f is the incident
irradiance (usually in W/m2) and c is the
speed of light in vacuum. Here, . If the surface is planar at an angle
α to the incident wave, the intensity across the surface will be geometrically reduced by the cosine of that angle and the component of the radiation force against the surface will also be reduced by the cosine of
α, resulting in a pressure: P_\text{incident} = \frac{I_f}{c} \cos^2 \alpha The momentum from the incident wave is in the same direction of that wave. But only the component of that momentum normal to the surface contributes to the pressure on the surface, as given above. The component of that force tangent to the surface is not called pressure.
Radiation pressure from reflection The above treatment for an incident wave accounts for the radiation pressure experienced by a black (totally absorbing) body. If the wave is
specularly reflected, then the recoil due to the reflected wave will further contribute to the radiation pressure. In the case of a perfect reflector, this pressure will be identical to the pressure caused by the incident wave: P_\text{emitted} = \frac{I_f}{c} thus
doubling the net radiation pressure on the surface: P_\text{net} = P_\text{incident} + P_\text{emitted} = 2 \frac{I_f}{c} For a partially reflective surface, the second term must be multiplied by the reflectivity (also known as the reflection coefficient of intensity), so that the increase is less than double. For a
diffusely reflective surface, the details of the reflection and geometry must be taken into account, again resulting in an increased net radiation pressure of less than double. If a reflection rate is \eta then the net radiation pressure on the surface: P_\text{net} = P_\text{incident} + \eta P_\text{emitted} = \frac{I_f (1 + \eta)}{c}
Radiation pressure by emission Just as a wave reflected from a body contributes to the net radiation pressure experienced, a body that emits radiation of its own (rather than reflected) obtains a radiation pressure again given by the irradiance of that emission
in the direction normal to the surface Ie: P_\text{emitted} = \frac{I_\text{e}}{c} The emission can be from
black-body radiation or any other radiative mechanism. Since all materials emit black-body radiation (unless they are totally reflective or at absolute zero), this source for radiation pressure is ubiquitous but usually tiny. However, because black-body radiation increases rapidly with temperature (as the fourth power of temperature, given by the
Stefan–Boltzmann law), radiation pressure due to the temperature of a very hot object (or due to incoming black-body radiation from similarly hot surroundings) can become significant. This is important in stellar interiors.
Radiation pressure in terms of photons Electromagnetic radiation can be
viewed in terms of particles rather than waves; these particles are known as
photons. Photons do not have a rest-mass; however, photons are never at rest (they move at the speed of light) and acquire a momentum nonetheless which is given by: p = \dfrac{h}{\lambda} = \frac{E_p}{c}, where is momentum, is the
Planck constant, is
wavelength, and is speed of light in vacuum. And is the energy of a single photon given by: E_p = h \nu = \frac{h c}{\lambda} The radiation pressure again can be seen as the transfer of each photon's momentum to the opaque surface, plus the momentum due to a (possible) recoil photon for a (partially) reflecting surface. Since an incident wave of irradiance over an area has a power of , this implies a flux of photons per second per unit area striking the surface. Combining this with the above expression for the momentum of a single photon, results in the same relationships between irradiance and radiation pressure described above using classical electromagnetics. And again, reflected or otherwise emitted photons will contribute to the net radiation pressure identically.
Compression in a uniform radiation field In general, the pressure of electromagnetic waves can be obtained from the
vanishing of the trace of the electromagnetic stress tensor: since this trace
equals 3P − u, we get P = \frac{u}{3}, where is the radiation energy per unit volume. This can also be shown in the specific case of the pressure exerted on surfaces of a body in
thermal equilibrium with its surroundings, at a temperature : the body will be surrounded by a uniform radiation field described by the
Planck black-body radiation law and will experience a compressive pressure due to that impinging radiation, its reflection, and its own black-body emission. From that it can be shown that the resulting pressure is equal to one third of the total
radiant energy per unit volume in the surrounding space. By using
Stefan–Boltzmann law, this can be expressed as P_\text{compress} = \frac{u}{3} = \frac{4\sigma}{3c} T^4, where \sigma is the
Stefan–Boltzmann constant. == Solar radiation pressure ==